Answer:
Covalent compound
Explanation:
It is formed by covalent bonds, in which the atoms share a pair of valence electrons
Answer:
The number of protons in an atom is always equal to the atomic number.
Explanation:
Answer:
8.08 grams
Explanation:
Given;
Mass of the steam, m = 100 g
Change in temperature of water = (95°C - 35°C) = 60°C
Change in temperature of steam = (110°C - 100°C) = 10°C
let the mass of water by 'M'
also,
We know
specific heat of water, c = 4.184 J/Kg.°C
And, specific heat of steam, C = 2.03 J/Kg.°C
Now,
Heat released = Mass × specific heat × change in temperature
thus, for the condition given in the question
M × 4.184 × 60 = 100 × 2.03 × 10
or
M = 8.08 grams
The mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110C to 100C is 125 grams. To solve this question, we used the specific heat of water, calculated the heat produced in the latter scenario, and deduced the mass needed from that.
To determine the mass of water that will provide the same amount of heat when cooled from 95.0 to 35.0 C as a 100 g of steam cooling from 110 to 100C, we need to first calculate the amount of heat produced in the latter situation. Using the specific heat of water which is 4.184 J/g °C, the heat produced when cooling 100g of steam from 110C to 100C is Q=msΔT, where m is mass, s is specific heat, and ΔT is temperature difference. So, Q = 100g * 4.184 J/g°C * (110°C - 100°C) = 4184 J.
Now, we have to calculate the mass of water that will produce the same amount of heat when cooled from 95°C to 35°C. We rearrange the equation to solve for mass. Hence, m = Q/sΔT = 4184 J / 4.184 J/g°C / (95.0 °C - 35.0 °C) = 125g. Therefore, 125g of water will provide the same amount of heat when cooled from 95.0 to 35.0 C.
#SPJ3
Given Mass of pure silver (Ag) = 265 mg
Silver chloride AgCl which is used in plating silver contains 75.27 % Ag
This means that:
A 100 mg of silver chloride contains 75.27 mg of silver
Therefore, the amount of silver chloride required to plate a sample containing 265 mg silver would correspond to:
265 mg Ag * 100 mg AgCl/75.27 mg Ag
= 352.1 mg AgCl
Answer:
0.35215 grams of silver chloride required to plate 265 mg of pure silver.
Explanation:
Mass of silver = 265 mg = 0.265 g
Moles of silver =
According to reaction, 2 moles of silver are obtained from 2 moles of silver chloride.
Then 0.002454 moles of silver will be obtained from :
of silver chloride
Mass of 0.002454 moles of silver chloride:
= 0.002454 mol × 143.5 g/mol = 0.35215 g
0.35215 grams of silver chloride required to plate 265 mg of pure silver.
Answer:
B
Explanation:
Newton's third law. states that:
Action and reaction are equal and opposite.