CHEMISTRY COLLEGE

Question 6 (5 points)In comparison to steam, ice has
A) less kinetic energy.
B)
more kinetic energy.
more total energy.
D) the same total energy.

Answers

Answer 1
Answer: A, I think
Ice cream is colder and steam is warmer, something cold has the atoms moving slower which means it has less kinetic energy.
Hope this helps!
Answer 2
Answer:

Answer:

its not more kinetic energy i put that and got it wrong

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6. A sample of nitrogen gas weighs 130 g. Write the chemical formula for nitrogen gas. Howmany molecules of elemental nitrogen is this? How many atoms of nitrogen are in this sample?

Answers

Chemical formula for nitrogen gas is N₂.

To find the number of molecules in the given sample, we have to convert the mass of the sample to moles by using the molecular mass of elemental nitrogen (N₂).

130gN_2\cdot(1molN_2)/(28gN_2)=4.64molN_2

Now, we have to use Avogadro's number (6.022x10^23) that indicates the number of molecules in one mole of substance:

4.64molN_2\cdot(6.022*10^(23)molecules)/(1molN_2)=2.79*10^(24)molecules

It means that there are 2.79x10^24 molecules of elemental nitrogen.

To find the number of atoms we just have to multiply the number of molecules by 2, which is the number of atoms of nitrogen per molecule of elemental nitrogen:

2.79*10^(24)molecules\cdot(2atoms)/(1molecule)=5.59*10^(24)atoms

There are 5.59x10^24 atoms of nitrogen in the sample.

How many amino acids are there and what three general categories do they fall into (i do not mean chemical categories in this question)? please include a one-sentence description of these three categories (3)?

Answers

Technically, there are an infinite number of possible amino acids, though we've found only 20 common ones that many organisms use and at least half a dozen obscure ones that specific organisms use. We focus only on the 20 common ones unless we're in a college level biochemistry course.

The three categories are nonpolar ones, polar ones, and charged ones. The nonpolar ones have non-polar side chains (no oxygens or nitrogens), the polar ones have polar side chains (most contain an OH group but no COOH group), the charged ones are either acidic or basic (has COOH group or a basic nitrogen).

15) What is the hydronium ion concentration [H3O + ] of a 0.125 M hydrocyanic acid solution with Ka = 4.9 × 10-10? The equation for the dissociation of hydrocyanic acid is: HCN(aq) + H2O(l) ⇌ H3O+(aq) + CN- (aq)

Answers

The hydronium ion concentration [H₃O⁺]=7.826 x 10⁻⁶

Further explanation

In general, the weak acid ionization reaction  

HA (aq) ---> H⁺ (aq) + A⁻ (aq)  

Ka's value  

\large {\boxed {\bold {Ka \: = \: \frac {[H ^ +] [A ^ -]} {[HA]}}}}

Reaction

HCN(aq) + H₂O(l) ⇌ H₃O⁺(aq) + CN⁻ (aq)

0.125

x                                   x               x

0.125-x                         x               x

\tt Ka=([H_3O^+][CN^-])/([HCN^-])

\tt 4.9* 10^(-10)=(x^2)/(0.125-x)\approx (x^2)/(0.125)\n\nx^2=6.125* 10^(-11)\n\nx=7.826* 10^(-6)

The two reactions above, show routes for conversion of an alkene into an oxirane. If the starting alkene is cis-3-hexene the configurations of the oxirane products, A and B are Product A: _______ Product B: _______ Will either of these two oxirane products rotate the plane of polarization of plane polarized light

Answers

Answer:

Product A and B : (2R,3S)-2,3-diethyloxirane and (2S,3R)-2,3-diethyloxirane.

Explanation:

A double bond is converted to an oxirane through oxidation by peracids e.g. mCPBA (meta-chloroperoxybenzoic acid).

Epoxidation can occur at both face of double bond result in formation of two stereoisomers.

Product A and B : (2R,3S)-2,3-diethyloxirane and (2S,3R)-2,3-diethyloxirane

Both A and B contain plane of symmetry. Hence, both the products are achiral. So, they do not rotate the plane of polarization of plane polarized light.

The rate constant for the second-order reaction 2NOBr(g) ¡ 2NO(g) 1 Br2(g) is 0.80/M ? s at 108C. (a) Starting with a concentration of 0.086 M, calculate the concentration of NOBr after 22 s. (b) Calculate the half-lives when [NOBr]0 5 0.072 M and [NOBr]0 5 0.054 M.

Answers

Explanation:

2NOBr(g) --> 2NO(g) 1 Br2(g)

Rate constant, k = 0.80

a) Initial concentration, Ao = 0.086 M

Final Concentration, A = ?

time = 22s

These parameters are connected with the equation given below;

1 / [A] = kt + 1 / [A]o

1 / [A] = 1 / 0.086 + (0.8 * 22)

1 / [A] = 11.628 + 17.6

1 / [A] = 29.228

[A] = 0.0342M

b) t1/2 = 1 / ([A]o * k)

when [NOBr]0 5 0.072 M

t1/2 = 1 / (0.072 * 0.80)

t1/2 = 1 / 0.0576 = 17.36 s

when [NOBr]0 5 0.054 M

t1/2 = 1 / (0.054 * 0.80)

t1/2 = 1 / 0.0432 = 23.15 s

Answer:

(a)

0.0342M

(b)

t_(1/2)=17.36s\nt_(1/2)=23.15s

Explanation:

Hello,

(a) In this case, as the reaction is second-ordered, one uses the following kinetic equation to compute the concentration of NOBr after 22 seconds:

(1)/([NOBr])=kt +(1)/([NOBr]_0)\n(1)/([NOBr])=(0.8)/(M*s)*22s+(1)/(0.086M)=(29.3)/(M)\n

[NOBr]=(1)/(29.2/M)=0.0342M

(b) Now, for a second-order reaction, the half-life is computed as shown below:

t_(1/2)=(1)/(k[NOBr]_0)

Therefore, for the given initial concentrations one obtains:

t_(1/2)=(1)/((0.80)/(M*s)*0.072M)=17.36s\nt_(1/2)=(1)/((0.80)/(M*s)*0.054M)=23.15s

Best regards.

How many moles of carbondioxide are produced when 0.2mol of sodium carbonate react with excess hydrovhloric acid

Answers

Answer:

0.2 moles of CO₂  are produced

Explanation:

Given data:

Moles of CO₂ produced = ?

Moles of Na₂CO₃ react = 0.2 mol

Solution:

Chemical equation:

Na₂CO₃ + 2HCl       →     2NaCl + CO₂ + H₂O

Now we will compare the moles of CO₂ with Na₂CO₃ .

                   Na₂CO₃          :             CO₂

                       1                  :               1

                    0.2                :             0.2

Thus, 0.2 moles of CO₂  are produced.
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