Answer:
6x+1
Step-by-step explanation:
hope this helps
Answer:
I think it is 5
Step-by-step explanation:
Here's how you could solve this problem:
(root of 5)√x^4 multiplied by (root of 5)√x^4
- combine like terms
- you should get (root 5)√x^8 -> because, with the Laws of Exponents, multiplying like terms with exponents is seen to be equivalent to adding the exponents
- finally, write out x^(5/5) multiplied by x^(3/5)
- this is because you've taken out the largest multiple of 5 in the exponent that you had (5 is the largest multiple of 5 out of 8), and you subtracted 8 by 5 to get the remaining exponent of the other term
- simply exponents, and you're done :D :D :D :D :D
81-25x^2
Simplify
5y+2w-5y+6w
Combine like terms
= 5y+2w+-5y+6
= ( 2w+6w)+ ( 5y+-5y)
= 8w
I hope that's help !
Answer: He will not have enough room
Step-by-step explanation: To determine if Andrew has enough room for his 250 CDs on the two shelves inside the bookcase, we need to calculate how many CD racks can fit on each shelf and how many CDs each of these racks can hold.
The bookcase is 3 ft wide, which is equivalent to 36 inches. Each shelf is 15 inches high. Therefore, the available space for CD racks on each shelf is 36 inches in width and 15 inches in height.
Each CD rack is 17 inches wide and 7 inches high. To calculate how many racks can fit on each shelf, we can use the following formula:
Number of racks on a shelf = (Width of shelf) / (Width of CD rack)
Number of racks on a shelf = 36 inches / 17 inches ≈ 2.12 (round down to 2, as you can't have a fraction of a rack)
Now, let's calculate how many CDs each of these racks can hold. Each CD rack can hold three stacks of 12 CDs each, for a total of 3 x 12 = 36 CDs.
So, on each shelf, Andrew can fit 2 CD racks, and each rack can hold 36 CDs. Therefore, each shelf can store 2 x 36 = 72 CDs.
Since Andrew has two shelves, he can store a total of 2 x 72 = 144 CDs in the bookcase.
So, he will be able to store 144 CDs in the bookcase, which is less than his 250 CDs. Therefore, he won't have enough room for all his 250 CDs in the bookcase, and he will need additional storage for the remaining CDs.
blue), and
• put a blue marble in the bag if the two marbles you drew are different colors.
Repeat this step (reducing the number of marbles in the bag by one each time) until only one
marble is left in the bag. What is the color of that marble?
The final marble left in the bag will be red.
Let, analyze the process step by step:
Initially, the bag contains 99 red marbles and 99 blue marbles.
When you take two marbles out of the bag, there are two possibilities: either you get two red marbles or two blue marbles, or you get one red and one blue marble.
a. If you get two marbles of the same color (both red or both blue), you put a red marble in the bag.
b. If you get one red and one blue marble, you put a blue marble in the bag.
After putting a marble back in the bag, you have one less marble in the bag.
You repeat this process, reducing the number of marbles in the bag by one each time, until only one marble is left in the bag.
Now, let's think about the outcomes at each step:
If the bag contains an odd number of marbles (99 red + 99 blue = 198), the final marble will be red because at each step, you are adding a red marble back to the bag.
If the bag contains an even number of marbles (e.g., 100 red + 100 blue = 200), the final marble will be blue because at each step, you are adding a blue marble back to the bag.
In this case, the bag contains 99 red marbles and 99 blue marbles, which is an odd number (198 marbles).
Therefore, the final marble left in the bag will be red.
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