Answer:
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a. What is the estimated percentile for a student who scores 425 on Writing?
b. What is the approximate score for a student who is at the 87th percentile for Writing?
Answer:
a) The estimated percentile for a student who scores 425 on Writing is the 30.5th percentile.
b) The approximate score for a student who is at the 87th percentile for Writing is 613.5.
Step-by-step explanation:
Problems of normally distributed distributions are solved using the z-score formula.
In a set with mean and standard deviation , the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
a. What is the estimated percentile for a student who scores 425 on Writing?
This is the pvalue of Z when X = 425. So
has a pvalue of 0.3050.
The estimated percentile for a student who scores 425 on Writing is the 30.5th percentile.
b. What is the approximate score for a student who is at the 87th percentile for Writing?
We have to find X when Z has a pvalue of 0.87. So X for Z = 1.126.
The approximate score for a student who is at the 87th percentile for Writing is 613.5.
Using cross multiplication you can determine that the ANSWER is 10.
Answer:
Step-by-step explanation:
We have been given an image of a triangle. We are asked to find the value of x.
We can see that triangle AFE is similar to triangle DFK. We know that corresponding sides of similar triangle are proportional, so we can set an equation to solve for x as:
Upon cross multiplying our given equation, we will get,
Therefore, the value of x is 10.
1
2
(x - 3) = 9
b. how old is Brandon
c. what was the difference in their ages 5 years ago?
d. what is the sum of their ages now?
e. what will the sum of their ages be two years from now?
f. what will the difference of their ages be two years from now
will mark the brainliest.
Answer: See explanation
Step-by-step explanation:
a. how old is Cheryl?
Cheryl's age = d + 5
b. how old is Brandon?
d + 5 + 2
= d + 7
c. what was the difference in their ages 5 years ago?
Cheryl age five years ago = d
Brandon's age five years ago = d + 2
Difference = d + 2 - d = 2 years
d. what is the sum of their ages now?
Cheryl's age = d + 5
Brandon age = d + 7
Sum = d + 5 + d + 7
= 2d + 12
e. what will the sum of their ages be two years from now?
Two years from now,
Cheryl's age = d + 5 + 2 = d + 7
Brandon age = d + 7 + 2 = d + 9
Sum = d + 7 + d + 9
= 2d + 16
f. what will the difference of their ages be two years from now
Two years from now,
Cheryl's age = d + 5 + 2 = d + 7
Brandon age = d + 7 + 2 = d + 9
Difference = Brandon age - Cheryl age
= (d + 9) - (d + 7)
= 2 years.
Answer:
0, 14
Step-by-step explanation:
-2, is 8 away from 6, so you add 8 to 6 to reflect it and get 14