4. Two cars are travelling along a straight road, as shown below. The pass each other at pointB and then continue in opposite directions. The red car travels for 0.25 hours from point B
to point C at a constant velocity of 32 km/hr east. The blue car travels for 0.25 hours from
points B to point D at a constant velocity of 48 km/hr. How far has each car traveled from
point B? What is the position of each car relative to the origin, point A?

Answers

Answer 1
Answer:

Using the speed - time relation, the distance moved by the cars from point B are 8 kilometers and 12 kilometers respectively.

Distance of car 1from Point B :

  • Speed of car × time traveled from point B

Distance traveled from point B = 32 × 0.25 = 8km

Distance of car 2from Point B :

  • Speed of car × time traveled from point B

Distance traveled from point B = 48 × 0.25 = 12km

The diagram isn't attached, hence question 2 cannot be answered accurately.

Therefore, the distance traveled from point B by car 1 and 2 is 8km and 12 km respectively.

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Answer 2
Answer:

Final answer:

The red car has traveled 8 km east of point B, while the blue car has traveled 12 km west of point B.

Explanation:

To determine how far each car has traveled, we need to use the formula: distance = speed × time. The red car travels for 0.25 hours at a constant velocity of 32 km/hr, so the distance it travels is: distance = 32 km/hr × 0.25 hr = 8 km. The blue car travels for the same amount of time at a constant velocity of 48 km/hr, so the distance it travels is: distance = 48 km/hr × 0.25 hr = 12 km.

The position of each car relative to the origin, point A, is as follows: The red car is 8 km east of point A (since its velocity is in the east direction). The blue car is 12 km west of point A (since its velocity is in the opposite direction to the east).

Learn more about Calculating distances and positions of two cars here:

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The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103 pascals? P (pascals) V (liters) 5.0 × 103 6.0 1.5 × 104 3.0 2.0 × 104 2.0 2.5 × 104 1.5

Answers

Answer:

17.23L

Explanation:

The table lists pressure and volume values for a particular gas. Which is the best estimate for the value of V at P = 7.0 × 103 pascals?

P (pascals)                  V (liters)     1/v

1. 5.0 × 10^3                  6.0       0.16

2. 1.5 × 10^4                     3.0      0.33

3. 2.0 × 10^4                    2.0      0.5

4. 2.5 × 10^4                    1.5         0.66

if we are to plot the above data in a linear graph, the equation of a line graph below can be used

y-y1=m(x-x1)

y-y1=(y2-y1)/(x2-x1)(x-x1)..............1

from the  ideal gas law

pressure is inversely proportional to volume as nRT is the constant of proportionality

PV=nRT

P=nRT/V

from equation 1

let y1= 1.5 × 10^4

y2= 2.0 × 10^4

x1=0.33

x2= 0.5

y-1.5x10^4=2.0 × 10^4-1.5 × 10^4 /(0.5-.33)(x-0.33)

y-1.5x10^4=29411(x-0.33)

y=15000-9705.88+29411x

y=5294+29411x

at 7*10^3

7*10^3=5294+29411x

x=0.058

recall that x=1/V

inverse of both sides gives volume to be

V=17.23L

I think the question need to use extrapolation. FInd the linear function of the first and second data. And then, the anwser is 5.4 liters.

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Answers

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Hope this helps!

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Answers

Answer:

0 J

Explanation:

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Answers

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Answers

Answer:

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Answers

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