Answer:
Explanation:
1) Increase the amount of charge on each object
2) Decrease the distance between each object
3) Increase the mass of the objects.
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Which of the following is a correct equilibrium expression?
A.
`"K"_("eq") = (["KOH"]^4["O"_2]^3)/(["KO"_2]^4["H"_2"O"]^2)`
B.
`"K"_("eq") = (["H"_2"O"]^2)/(["O"_2]^3)`
C.
`"K"_("eq") = (["KO"_2]^4["H"_2"O"]^2)/(["KOH"]^4["O"_2]^3)`
D.
`"K"_("eq") = (["O"_2]^3)/(["H"_2"O"]^2)`
Answer:
Answer is option D
Explanation:
The explanation is embedded in the word document attached
Answer:
Keq= [KOH]^4 [O2]^3/[[KO2]^4
Explanation:
4KO2(s) + 2H2O(l) → 4KOH(s) + 3O2(g)
Looking at the equation, the correct equilibrium expression is shown in the answer. The equilibrium constant for a reaction is given by the active masses of species involved in the reaction. The relative molar coefficients of species are raised to the power of their molar concentrations to give the active mass of each specie. This active mass now goes into the equilibrium equation.
Water is not included in the equilibrium equation because, as a solvent, it is present in large excess.
it would be 0.75 atm
a) The concentrated solution has the same amount of solute as the dilute solution.
b) The concentrated solution has more solute than the dilute solution.
c) The concentrated solution has a different amount of solute than the dilute solution.
d) The concentrated solution has the same amount of solute as the dilute solution.
Answer: b) The concentrated solution has more solute than the dilute solution.
Explanation:-
Binary Solution is a homogeneous mixture of two components called as solute and solvent. Solute is the component which is present in smaller proportion and is solid for solid in liquid solution and solvent is the component which is present in larger proportion and is liquid for solid in liquid solution.
Concentrated solution is one in which there is more amount of solid.
Dilute solution is one in which there is more amount of liquid.
Answer:
a) 1
Explanation:
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b. NH4S
The separation of ammonium sulfide has been possible with filter paper.
Thus, option B is correct.
The dissolution or solubility of the compound has been used for the determination of the sample actions.
The compounds that are soluble has been not be visible independently. The undissolved solute in the sample has been clearly visible discreet in the solution, resulting in the separation by physical means.
Filter paper has been the small pore size material that has been used for the physical separation of the compounds in heterozygous solution.
The solution of NaCl and water has been pure solution, and thus the separation of NaCl has not been possible with the filter paper.
The solution of ammonium sulfide and water has been a heterozygous solution, as ammonium sulfide precipitate out in the solution. Thus, the separation of ammonium sulfide has been possible with filter paper.
Thus, option B is correct.
For more information about, filter paper, refer to the link:
The compound when stirred in water will not pass through filter paper is NH4S. The answer is letter B. This is because it is a precipitate that resulted from the reaction of an acid or a base. NaCl will pass through the filter paper because it is soluble in water.