Solve for y
12.6x-4.2y=8.4

Answers

Answer 1
Answer:

Answer:

-8.4 to 8.4 and 12.6

Step-by-step explanation:


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A student said that m<1=80 degrees. what error did the student make

Answers

The error the student made is referring to an angle, m<1, being equal to 80 degrees. It is incorrect to assign a measurement or value to an angle without any given information or reference point.

The ordered pair (0,4) is a solution of what system?

Answers

I can think of one
(x,y) format
if x=0, y=4 soo
y=x+4 is one equation

What is the value of 36x-8y2 when x=3 and y=-6

Answers

Assuming that the 2 after the y means squared...

36x3=108
-6x-6=36
8x36=288
108-288=-180

A hyperbola has vertices (+-5,0) and one focus (6,0) what is the standard form equation of the hyperbola.

Answers

The standard form equation of the hyperbola:
x² / a² - y² / b² = 1
a = 5,
a² = 25
c = 6
c² = a² + b²
36 = 25 + b²
b² = 36 - 25
b² = 11
Answer:
x²/25  -  y²/11 = 1 

Final answer:

The standard form equation for this hyperbola, when vertices are (+-5,0) and one focus is (6,0), is x²/25 - y²/11 = 1.

Explanation:

In the question, we are given a hyperbola with vertices at (+-5,0) and one focus at (6,0). A hyperbola is defined by its distances from a given point to the two different foci, and its standard form equation along the x-axis can be written as

(x-h)²/a² - (y-k)²/b² = 1

, where (h, k) is the center of the hyperbola, a represents the distance from the center to each vertex, and b represents the distance from the center to each co-vertex. In this case,

h = 0

, since the center of the hyperbola is at the origin. The value of

a = 5

is the distance from the center to each vertex. Finally, the square of the distance c from the center to each focus is defined as

c² = a² + b²

, so we can find

b = sqrt(c² - a²)

. Here, c = 6, so b = sqrt(6² - 5²) = sqrt(11). Thus, the standard form equation of this hyperbola is

x²/25 - y²/11 = 1

.

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Perform the operations, multiply, and simplify.
-a^3b (3a^2 b^5 - ab^4 - 7a ^2 b)

Answers

-a^3b (3a^2 b^5 - ab^4 - 7a ^2 b)=\n -3a^5b^6+a^4b^5+7a^5b^2
-a^3b (3a^2 b^5 - ab^4 - 7a ^2 b) \n \n =-3a^5b^6-(-a^4b^5)-(-7a^5b^2) \n \n =-3a^5b^6+a^4b^5+7a^5b^2

Jeremy is 29 years old and in good health. What is the annual premium for the cheapest policy having a $90,000 face value that Jeremy can buy?For age 29, a male whole life if 18.25, 20-payment life is 31.39, and 20-year endowment is 39.69.


a.

$1,825

b.

$1,294

c.

$1,929

d.

$1,643

i just did it and its D

Answers

1643 is the annual premium for the cheapest policy Jeremy can buy.

What is Annual Premium?

The amount of money a business or an individual pays for a policy annually is called the annual premium.

Face value is the amount of benefits in the form of money or other beneficiaries a policy holder receives at maturity.

Age of Jeremy = 29

Face value of the policy = $90,000

Estimated annual premium = (Face value ÷ 1000) × rate

Annual premium payable for a man whole life = (90,000 ÷ 1000) × 18.25

                                                                             = 90 × 18.25

                                                                             = 1642.5 ≅ 1643

Hence, Annual premium for the cheapest policy having a 90,000 face value that Jeremy can buy is $1643.

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Answer:

Step-by-step explanation:

D