Find each percent increase. Round to the nearest percent
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Answer 1
Answer:

Answer:

1. 15 to 21 = 21 - 15 / 15 = 0.4*100% = 40%

2. 12 teachers to 48 teachers = 48 - 12/48 = 0.75 * 100% = 75%

3. 80 pencil to 120 pencil = 120 - 80 / 80 = 0.5*100% = 50%

4. 40 cans to 70 cans = 70 - 40 / 70 = 0.43 * 100% = 43%


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Identify the distance, to the nearest tenth, between C(−7,−9) and J(6,2).

Answers

Answer:

The answer is 17.02, to the nearest tenth is 17.

Step-by-step explanation:

Under the radical, that us take the square root of the following sum:

(Jx - Cx )^2 + (Jy - Cy)^2

Substitute in the values:

(6 - (-7))^2 + (2 - (-9))^2 =

This becomes:

(6+7)^2 + (2 + 9)^2 =

13^2 + 11^2 =

169 + 121 =

Sqrt 290 =

17.029 = To the nearest 10th is 17

The figure below is a scale drawing of a garden. If the scale used 1/4 inch = 3 feet, then what is the perimeter of the actual garden?

Answers

Answer:

The answer is 2.25

Step-by-step explanation:

Steps:

1. 1/2 inch + 1 3/4 inch = 2.25 inch

Answer:

2.25

Step-by-step explanation:

The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0, 0.3, 0.4, and 0.6, respectively. The probabilities of no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0.8, 0.02, 0.08, and 0.1, respectively. a. Determine the probability of high ink viscosity given poor print quality.
b. Given poor print quality, what problem is most likely?

Answers

Answer and explanation:

Given : The probabilities of poor print quality given no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0, 0.3, 0.4, and 0.6, respectively.

The probabilities of no printer problem, misaligned paper, high ink viscosity, or printer-head debris are 0.8, 0.02, 0.08, and 0.1, respectively.

Let the event E denote the poor print quality.

Let the event A be the no printer problem i.e. P(A)=0.8

Let the event B be the misaligned paper i.e. P(B)=0.02

Let the event C be the high ink viscosity i.e. P(C)=0.08

Let the event D be the printer-head debris i.e. P(D)=0.1

and the probabilities of poor print quality given printers are

P(E|A)=0,\ P(E|B)=0.3,\ P(E|C)=0.4,\ P(E|D)=0.6

First we calculate the probability that print quality is poor,

P(E)=P(A)P(E|A)+P(B)P(E|B)+P(C)P(E|C)+P(D)P(E|D)

P(E)=(0)(0.8)+(0.3)(0.02)+(0.4)(0.08)+(0.6)(0.1)

P(E)=0+0.006+0.032+0.06

P(E)=0.098

a. Determine the probability of high ink viscosity given poor print quality.

P(C|E)=(P(E|C)P(C))/(P(E))

P(C|E)=(0.4* 0.08)/(0.098)

P(C|E)=(0.032)/(0.098)

P(C|E)=0.3265

b. Given poor print quality, what problem is most likely?

Probability of no printer problem given poor quality is

P(A|E)=(P(E|A)P(A))/(P(E))

P(A|E)=(0* 0.8)/(0.098)

P(A|E)=(0)/(0.098)

P(A|E)=0

Probability of misaligned paper given poor quality is

P(B|E)=(P(E|B)P(B))/(P(E))

P(B|E)=(0.3* 0.02)/(0.098)

P(B|E)=(0.006)/(0.098)

P(B|E)=0.0612

Probability of printer-head debris given poor quality is

P(D|E)=(P(E|D)P(D))/(P(E))

P(D|E)=(0.6* 0.1)/(0.098)

P(D|E)=(0.06)/(0.098)

P(D|E)=0.6122

From the above conditional probabilities,

The printer-head debris problem is most likely given that print quality is poor.

Answer:

Answer of Part(a) is 16/49

and Answer of Part(b) is Printer-head debris

Step-by-step explanation:

Answer is in the following attachment

Anyone good with matrixes and matrices? please help me i need help with 10 questions and I need to raise my grade ASAP please

Answers

Answer:

what questions need to be done? We need to know the problems before we answer them. :/

Which expression is equivalent to StartRoot 200 EndRoot?A) 2 StartRoot 10 EndRoot
B) 10 StartRoot 2 EndRoot
C) 10 StartRoot 20 EndRoot
D) 100 StartRoot 2 EndRoot

Answers

Answer:

Answer

is B

10√2

Step-by-step explanation:

is: √200

Simplifying the given expression, we get:

200 = 2 x 2 x 2 x 5 x 5

⇒ 200 = (2)² x (5) ² x 2

Answer:

b

Step-by-step explanation:

The sum of two numbers is -14, if one number is subtracted from the other, their difference is 2, find the numbers.

Answers

Answer:uu

-10 and -12

Step-by-step explanation:

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