Do these pairs of values (x and y) represent two quantities that are proportional?HELP ME PLEASE

Answer:

a) 0.2119 = 21.19% probability that the average percent of fat calories consumed is more than thirty-seven.

b) The first quartile for the average percent of fat calories is 33.31

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean and standard deviation , the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean and standard deviation , a large sample size can be approximated to a normal distribution with mean and standard deviation

In this problem, we have that:

(a) For the group of 16 individuals, find the probability that the average percent of fat calories consumed is more than thirty-seven. (Round your answer to four decimal places.)

This is the 1 subtracted by the pvalue of Z when X = 37. So

By the Central Limit Theorem

has a pvalue of 0.7881

1 - 0.7881 = 0.2119

0.2119 = 21.19% probability that the average percent of fat calories consumed is more than thirty-seven.

b) Find the first quartile for the average percent of fat calories. (Round your answer to two decimal places.) percent of fat calories

The 1st quartile is the 25th percentile. So this is the value of X when Z has a pvalue of 0.25. So it is X when Z = -0.675. So

The first quartile for the average percent of fat calories is 33.31

The diameter οf the circle is 28/π inches οr apprοximately 8.89 inches (rοunded tο twο decimal places).

The fοrmula fοr the circumference (C) οf a circle is given by:

C = 2πr

where r is the radius οf the circle.

If the circumference οf the circle is 28 inches, we can sοlve fοr the radius by dividing bοth sides οf the equatiοn by 2π:

C/2π = r

Substituting the given value οf C = 28, we get:

r = 28/2π

r = 14/π

Finally, tο find the diameter (d) οf the circle, we multiply the radius by 2:

d = 2r

Substituting the value οf r = 14/π, we get:

d = 2(14/π) = 28/π

Therefοre, the diameter οf the circle is 28/π inches οr apprοximately 8.89 inches (rοunded tο twο decimal places).

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Answer:

Step-by-step explanation:

So, out of a 100% students that drop out, 9,2% is in the range of 16-17 years of age. The conclusion would be, would express the probability of randomly picking a dropout that belong in this set of 16-17 year olds.

Notice that I put "1000" because I want a 0,0092 as a multiplier, because in probability, that represents "9,2%". You actually awnt to always put 100, because that's 100%, but this is just a trick, writing 9,2/100 still works.

Now, for the second bit of information you want to also include that "6,2% white students", which is a subset of the set of 16-17 year olds. and that's a probability, in of itself. Thus, you multiply these two probabilities.

What you want to plug, in your calculator, the follwing expression:

This will give you a number, which you'll have to multiply by 100, to obtain the answer for your problem!

Final answer:

The probability that a randomly selected dropout aged 16 to 17 is white, given the provided statistics, is 67.39%.

Explanation:

The student is asking a question related to conditional probability in the field of Mathematics. The question prompts us to find out the probability that a randomly selected high school dropout in the age range of 16 to 17 is white. To find the answer, we use the following formula:

P(A|B) = P(A ∩ B) / P(B)

Where:
P(A|B) is the probability of event A happening given that event B has occurred.
P(A ∩ B) is the probability of both event A and event B happening together.
P(B) is the probability of event B happening.

From the problem statement, we know that P(B), the percentage of dropouts who are 16-17 years old, is 9.2%. Also, P(A ∩ B), the percent of dropouts who are both white and 16-17 years old, is given as 6.2%. We are supposed to find P(A|B), the probability that a dropout is white given that they are 16-17 years old.

Therefore, by substituting these values into the formula, we get:

P(A|B) = 6.2% / 9.2% = 67.39%

Rounded to two decimal places, the answer is 67.39%. So, there is approximately a 67.39% chance that a random high school dropout aged 16-17 is white.

Learn more about Conditional Probability here:

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Answer:

Yes students should be confident in addition before they proceed to mulplication.This is because addition is the base of multiplication and requires mastery before you start,so It would be much easier to solve

Answer:

75% are rock and roll

Step-by-step explanation:

6 /8 = 3/4 = 0.75 = 75%