HELP IT'S DUE TONIGHT!!!!! If a piece of steel 12 feet long weighs 168 pounds, how much will a piece of steel 20 feet long weigh?

Answers

Answer 1
Answer:

Answer:

280lbs

Step-by-step explanation:

168/12=14

14×20=280


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Assume that a lost treasure will be in a certain area of the ocean with probability 0.4, and that a search of that area will find the treasure with probability 0.9 if it is there. What is the conditional probability of the treasure being in the area if the area is searched and no treasure is found?
In the diagram, how many pairs of vertical angles are shown? ​
HELP ASAP WILL MARK BRAINLY
The image of a parabolic lens is traced onto a graph. The function f(x) = 1/4 (x+8)(x-4) represents the image. Atwhich points does the image cross the x-axis? O (-8, 0) and (4,0) (8,0) and (-4, 0) O (2, 0) and (-1,0) O (-2, 0) and (1, 0)

In a triangle, the measure of the second angle is twice the measure of the first angle. The third angle is equal to the sumof the other angles,
Which of the following could represent the measures of the three angles?
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OX, 2x, 2x

Answers

Answer:

x, 2x, 3x

Step-by-step explanation:

If we have angle x as one angle, and the 2nd angle is twice the angle, the 2nd angle will be 2x. If the 3rd angle is the sum of the 1st angle and the 2nd angle, we have 2x + x, which equals 3x.

1. 2x2 + 3xy + 3xy is equivalent to

Answers

Answer:

2x2+6xy

Step-by-step explanation:

  • 2x2+3xy+3xy
  • Combine like terms, 2x2+6xy

What is the value? 3/4 + 7/12 - (-4)

Answers

Answer: 3/4 + 7/12 - (-4) = 3/4 + 7/12 + 4 (two minuses make a plus)

3/4 + 7/12 + 4/1 = 9/12 + 7/12 + 48/12           (4 = 4/1 or 4 divided by 1)  

(to add the fractions the denominators need to be the same. Multiply both the denominator and numerator by the same number)

(9+7+48)/12 = 64/12 = 5 and 1/3 or 16/3

We can also get this answer by leaving the 4 as a whole number:

9/12 + 7/12 +4 = 16/12 + 4 = 1 and 1/3 + 4 = 5 and 1/3

If you put the sum in a calclator you also get 5 and 1/3.

Hope this helps :)

The administration of a large university is interested in learning about the types of wellness programs that would interest its employees. To do this, they plan to survey a random sample of employees. Under consideration are several plans for selecting the sample. Which of the following sampling strategies is the stratified sampling?A. Simple Random Sampling.
B. Stratified Sampling.
C. Cluster Sampling.
D. Systematic Sampling.
E. Convenience Sampling.

Answers

Answer:

a. There are five categories of employees (administration faculty, professional staff, clerical and maintenance). Randomly select ten individuals from each category.

Completed question;

The administration of a large university is interested in learning about the types of wellness programs that would interest its employees. To do this, they plan to survey a random sample of employees. Under consideration are several plans for selecting the sample. Which of the following sampling strategies is the stratified sampling?

a. There are five categories of employees (administration faculty, professional staff, clerical and maintenance). Randomly select ten individuals from each category.

b. Fach employee has an ID number. Randomly select 50 numbers.

c. Randomly select a school within the university (eg, Business School) and survey all of the individuals (administration, faculty, professional staff, clerical and maintenance) who work in that school.

d. The HR Department has an alphabetized list of newly hired employees (hired within the last five years). After starting the process by randomly selecting an employee from the list, then every 5th name is chosen to be included in the sample.

Step-by-step explanation:

Stratified sampling is a sampling strategy from a population that involves sampling by dividing or partitioning the population into smaller subgroups.

So the correct answer is "There are five categories of employees (administration faculty, professional staff, clerical and maintenance). Randomly select ten individuals from each category." because it involves dividing the population into subgroups.

5 years ago, Cheryl was d years old, Brandon is 2 years older than Cheryl.a. how old is Cheryl

b. how old is Brandon

c. what was the difference in their ages 5 years ago?

d. what is the sum of their ages now?

e. what will the sum of their ages be two years from now?

f. what will the difference of their ages be two years from now

will mark the brainliest.

Answers

Answer: See explanation

Step-by-step explanation:

a. how old is Cheryl?

Cheryl's age = d + 5

b. how old is Brandon?

d + 5 + 2

= d + 7

c. what was the difference in their ages 5 years ago?

Cheryl age five years ago = d

Brandon's age five years ago = d + 2

Difference = d + 2 - d = 2 years

d. what is the sum of their ages now?

Cheryl's age = d + 5

Brandon age = d + 7

Sum = d + 5 + d + 7

= 2d + 12

e. what will the sum of their ages be two years from now?

Two years from now,

Cheryl's age = d + 5 + 2 = d + 7

Brandon age = d + 7 + 2 = d + 9

Sum = d + 7 + d + 9

= 2d + 16

f. what will the difference of their ages be two years from now

Two years from now,

Cheryl's age = d + 5 + 2 = d + 7

Brandon age = d + 7 + 2 = d + 9

Difference = Brandon age - Cheryl age

= (d + 9) - (d + 7)

= 2 years.

A rumor spreads through a small town. Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor. a. Write the differential equation satisfied by y in terms of proportionality k.
b. Find k (in units of day−1, assuming that 10% of the population knows the rumor at time t=0 and 40% knows it at time t=2 days.
c. Using the assumptions in part (b), determine when 75% of the population will know the rumor.
d. Plot the direction field for the differential equation and draw the curve that fits the solution y(0)=0.1 and y(0)=0.5.

Answers

Answer:

The answer is shown below

Step-by-step explanation:

Let y(t) be the fraction of the population that has heard the rumor at time t and assume that the rate at which the rumor spreads is proportional to the product of the fraction y of the population that has heard the rumor and the fraction 1−y that has not yet heard the rumor.

a)

(dy)/(dt)\ \alpha\  y(1-y)

(dy)/(dt)=ky(1-y)

where k is the constant of proportionality, dy/dt =  rate at which the rumor spreads

b)

(dy)/(dt)=ky(1-y)\n(dy)/(y(1-y))=kdt\n\int\limits {(dy)/(y(1-y))} \, =\int\limit {kdt}\n\int\limits {(dy)/(y)} +\int\limits {(dy)/(1-y)}  =\int\limit {kdt}\n\nln(y)-ln(1-y)=kt+c\nln((y)/(1-y)) =kt+c\ntaking \ exponential \ of\ both \ sides\n(y)/(1-y) =e^(kt+c)\n(y)/(1-y) =e^(kt)e^c\nlet\ A=e^c\n(y)/(1-y) =Ae^(kt)\ny=(1-y)Ae^(kt)\ny=(Ae^(kt))/(1+Ae^(kt)) \nat \ t=0,y=10\%\n0.1=(Ae^(k*0))/(1+Ae^(k*0)) \n0.1=(A)/(1+A) \nA=(1)/(9) \n

y=((1)/(9) e^(kt))/(1+(1)/(9) e^(kt))\ny=(1)/(1+9e^(-kt))

At t = 2, y = 40% = 0.4

c) At y = 75% = 0.75

y=(1)/(1+9e^(-0.8959t))\n0.75=(1)/(1+9e^(-0.8959t))\nt=3.68\ days