MATHEMATICS HIGH SCHOOL

When a number is increased by 39, the result
is 47. What equation fits this statement?

Answers

Answer 1
Answer:

Answer:

×+39=47

Step-by-step explanation:

is what I think because reult is 47so =47 and 39 is positive so x +39

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How much sand would it take to fill a sandbox that is 15 feet long, 10 feet wide, and 2 feet high?

Answers

V=legnth times width times height
legnth=15
width=10
height=2
V=15 times 10 times 2
V=300 ft^3

300 cubic feet ofsand

What are the solutions to the quadratic equation 3(x − 4)^2 = 75?a- x = −9 and x = 1
b- x = −5 and x = 5
c- x = −4 and x = 4
d- x = −1 and x = 9

Answers

the answer is (d) where x = -1 & 9

Need help asap will mark brainliest

Answers

Answer:

1725 ft²

Step-by-step explanation:

(50+65)/(2) *30 = (115)/(2) *30= 57.5*30 = 1725

Answer:

1,950 ft

Step-by-step explanation:

it is a compound shape, thus it is made up of a square and a triangle

you can find the area of the square by 30 x 50 and the area of the triangle by 30 as the height and 65 - 50 as the base, and when you add it together you get 1,950

The concrete company charges ​$130 for delivering less than yd Superscript 3 of concrete. For yd Superscript 3 and​ more, the charge is ​$​/yd Superscript 3 with a fraction of a yard charged as a fraction of ​$.65 Use function notation to write the charge as a function of the number x of cubic yards​ delivered, where 0x​10, and graph this function. Question content area bottom Part 1 Choose the correct function below.

Answers

Answer:

Step-by-step explanation:

To write the charge as a function of the number of cubic yards delivered, we can define two separate cases:

Case 1: For deliveries less than yd³, the charge is a flat fee of $130.

Case 2: For deliveries of yd³ or more, the charge is $/³, where a fraction of a yard is charged as a fraction of $0.65.

Let's use function notation to write the charge as a function of the number of cubic yards delivered, where 0 ≤ ≤ 10.

The function can be written as:

\[

() =

\begin{cases}

130 & \text{if } < \\

0.65(-) + \frac{}{} & \text{if } ≥ \\

\end{cases}

\]

Here, () represents the charge for cubic yards delivered, and is the threshold value in cubic yards where the charge changes.

To graph this function, we can plot points on a coordinate plane by choosing different values for and . The resulting graph will have two parts: a flat line representing the flat fee of $130 for < , and a linear line representing the variable charge of $/ for ≥ . The point where these two lines meet will be the threshold value (, 130).

Which of the following best explains why tan 5pi/6 does not equal to tan 5pi/3?A. The angles do not have the same reference angle.
B. Tangent is positive in the second quadrant and negative in the fourth quadrant.
C. Tangent is negative in the second quadrant and positive in the fourth quadrant.
D. The angles do not have the same reference angle or the same sign.

Answers

Option A. The angles do not have the same reference angle.

Explanation:

1) Angle 5π / 3 radians:

  • Convert radians to degrees: 5π/3 × 180° / π = 300°
  • 300° is in the fourth quadrant
  • The reference angle for angles in the fourth quadrant is 360° - angle ⇒ 360° - 300° = 60°.
  • ∴ The reference angle for this angle is 60°.

2) Angle 5π / 6 radians:

  • Convert radians to degrees: 5π/6 × 180° / π = 150°
  • 150° is in the second quadrant
  • The reference angle for angles in the second quadrant is 180° - angle ⇒ 180° - 150° = 30°.
  • ∴ The reference angle for this angle is 30°.

3) Conclusion:

  • Since the reference angles are different, the tangent ratios have different values.
  • tan (5π/3) = - tan(60°) = - √3
  • tan (5π/6) = - tan(30°) = - (√3)/3

Note that the tangent is negative in both second and fourth quadrants.

Answer:

The correct option is A.

Step-by-step explanation:

The first expression is,

\tan ((5\pi)/(6))

\tan ((6\pi-\pi)/(6))

\tan (\pi-(\pi)/(6))

The reference angle is (\pi)/(6) . In second quadrant the sign of tangent is negative.

-\tan ((\pi)/(6))

-(1)/(√(3))

The second expression is,

\tan ((5\pi)/(3))

\tan ((6\pi-\pi)/(3))

\tan (2\pi-(\pi)/(3))

The reference angle is (\pi)/(3) . In fourth quadrant the sign of tangent is negative.

-\tan ((\pi)/(3))

-√(3)

Since the sign are same but the reference angle is are different, therefore the correct option is A.

Dylan is at a fruit farm. So far he has 12 apples, Dylan starts walking and checks his basket, he only has 2 apples now. How many apples did Dylan lose?

Answers

on his way walking dylan lost atleast 10 apples
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