If Coach Smith has 12 players and each player needs three uniforms, three shin guards, two balls, and three pairs of cleats. How much will he end up spending on his equipment for the entire soccer team?

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Answer 1

Answer:

you can't do that. there isn't enough detail. we don't know how much each item costs

Related Questions

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What is the solution of the equation (x - 5)2 +3(x-5)+9 = 0? Use u substitution and the quadratic formula to solve.

• Water tank A has 220 gallons of water and is being drained at a constant rate of 5 gallons per minute.• Water tank B has 180 gallons of water and is being drained at a constant rate of 3 gallons per minute.
Part
How much time, in minutes, do water tank A and water tank B have to be drained in order for them to have the same amount of water?

Answers

Answer: In 20 minutes, tanks A and B will each have 120 gallons remaining in them.

Step-by-step explanation:

The equation, the amount at which they will be equal, represents the given starting amounts minus the gal/min times the unknown time in minutes, m.

220 - 5m = 180 - 3m Subtract 180 from both sides; add 5m to both sides.

220-180 -5m +5m = 180-180 +5m - 3m Combine like terms

40 = 2m Divide both sides by 2

20 = m

Check: Substitute 20 for m in the equation

220 - 5(20) = 180 - 3(20)

220 - 100 = 180 -60

120 = 120 True!

Find an equation in standard form for the ellipse with the vertical major axis of length 10 and minor axis of length 8

Answers

Answer: The required equation of the ellipse in standard form is $(y^2)/(25)+(x^2)/(16)=1.$

Step-by-step explanation: We are given to find the equation of an ellipse in standard form with the vertical major axis of length 10 units and minor axis of length 8 units.

Since the major axis is vertical, so it will lie on the Y-axis. Let the standard form of the ellipse be given by

$(y^2)/(a^2)+(x^2)/(b^2)=1,~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

where the length of major axis is 2a units and length of minor axis is 2b units.

According to the given information, we have

$2a=10\n\n\Rightarrow a=(10)/(2)\n\n\Rightarrow a=5$

and

$2b=8\n\n\Rightarrow b=(8)/(2)\n\n\Rightarrow b=4$

Substituting the values of a and b in equation (i), we get

$(y^2)/(5^2)+(x^2)/(4^2)=1\n\n\n\Rightarrow (y^2)/(25)+(x^2)/(16)=1.$

Thus, the required equation of the ellipse in standard form is $(y^2)/(25)+(x^2)/(16)=1.$

(x/h)^2+(y/v)^2=1 where h is the horizontal radius and v is the vertical radius

In this question it seem that they are saying the length of the axis and not radius so I would cut them in half so that they are radii...then:

(x/4)^2+(y/5)^2=1

x^2/16+y^2/25=1

In the past, 44% of those taking a public accounting qualifying exam have passed the exam on their first try. Latterly, the availability of exam preparation books and tutoring sessions may have improved the likelihood of an individual’s passing on his first try. In a sample of 250 recent applicants, 130 passed on their first attempt. At the 0.05 level of significance, what is the calculated value of test statistic? (Specify your answer to the 2nd decimal.)

Answers

Answer:

The calculated value of test statistic is z=2.48.

This has a P-value of P=0.00657.

If we state the null hypothesis $H_0: \pi\leq0.44$ at a significance level of $\alpha=0.05$ , we would reject this null hypothesis as $P-value<\alpha$ .

Step-by-step explanation:

We have in this problem, a hypothesis test of proportions.

The test statistic for this is the z-value, and is calculated like that:

$z=(p-\pi-0.5/N)/(\sigma)$

Where the term 0.5/N is the correction for continuity and is negative in the cases that p>π.

p: proportion of the sample; π: proportion of the population; σ: standard deviation of the population.

The standard deviation of the population has to be calculated as:

$\sigma=\sqrt{(\pi(1-\pi))/(N) } =\sqrt{(0.44(1-0.44))/(250) }=√(0.0009856)=0.0314$

The proportion of the sample (p) is $p=130/250=0.52$ .

Then, the test statistic z is

$z=(p-\pi-0.5/N)/(\sigma)=(0.52-0.44-0.5/250)/(0.0314) =(0.078)/(0.0314) =2.48$

The P-value of this statistic is P(z>2.48)=0.00657

If we state the null hypothesis $H_0: \pi\leq0.44$ at a significance level of $\alpha=0.05$ , we would reject this null hypothesis as $P-value<\alpha$ .

A cylindrical can without a top is made to contain 25 3 cm of liquid. What are the dimensions of the can that will minimize the cost to make the can if the metal for the sides will cost $1.25 per 2 cm and the metal for the bottom will cost $2.00 per 2 cm ?

Answers

Answer:

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Step-by-step explanation:

Given that, the volume of cylindrical can with out top is 25 cm³.

Consider the height of the can be h and radius be r.

The volume of the can is V= $\pi r^2h$

According to the problem,

$\pi r^2 h=25$

$\Rightarrow h=(25)/(\pi r^2)$

The surface area of the base of the can is = $\pi r^2$

The metal for the bottom will cost $2.00 per cm²

The metal cost for the base is =$(2.00× $\pi r^2$ )

The lateral surface area of the can is = $2\pi rh$

The metal for the side will cost $1.25 per cm²

The metal cost for the base is =$(1.25× $2\pi rh$ )

$=\$2.5 \pi r h$

Total cost of metal is C= 2.00 $\pi r^2$ + $2.5 \pi r h$

Putting $h=(25)/(\pi r^2)$

$\therefore C=2\pi r^2+2.5 \pi r * (25)/(\pi r^2)$

$\Rightarrow C=2\pi r^2+ (62.5)/( r)$

Differentiating with respect to r

$C'=4\pi r- (62.5)/( r^2)$

Again differentiating with respect to r

$C''=4\pi + (125)/( r^3)$

To find the minimize cost, we set C'=0

$4\pi r- (62.5)/( r^2)=0$

$\Rightarrow 4\pi r=(62.5)/( r^2)$

$\Rightarrow r^3=(62.5)/( 4\pi)$

⇒r=1.71

Now,

$\left C''\right|_(x=1.71)=4\pi +(125)/(1.71^3)>0$

When r=1.71 cm, the metal cost will be minimum.

Therefore,

$h=(25)/(\pi* 1.71^2)$

⇒h=2.72 cm

Therefore the radius of the can is 1.71 cm and height of the can is 2.72 cm.

Evaluate −b2−2bx2−x when x=−2.

Answers

An expression is defined as a set of numbers, variables, and mathematical operations. The value of −b²−2bx²−x when the value of x=-2 is −b²−8b + 4.

What is an Expression?

In mathematics, an expression is defined as a set of numbers, variables, and mathematical operations formed according to rules dependent on the context.

The value of the expression −b²−2bx²−x will be,

−b² − 2bx² − x

= − b² − 2b(-2)² − (-2)

= − b² − 8b + 4

Hence, the value of −b²−2bx²−x when the value of x=-2 is −b²−8b + 4.

Learn more about Expression:

brainly.com/question/13947055

#SPJ2

The answer...... is 6x+2

Television viewing reached a new high when the global information and measurement company reported a mean daily viewing time of hours per household. Use a normal probability distribution with a standard deviation of hours to answer the following questions about daily television viewing per household. a. What is the probability that a household views television between 3 and 9 hours a day (to 4 decimals)? b. How many hours of television viewing must a household have in order to be in the 2%top of all television viewing households (to 2 decimals)? hours c. What is the probability that a household views television more than hours a day (to 4 decimals)?

Answers

Answer:

(a) The probability that a household views television between 3 and 9 hours a day is 0.5864.

(b) The viewing hours in the top 2% is 13.49 hours.

Step-by-step explanation:

Let X = daily viewing time of of television hours per household.

The mean daily viewing time is, μ = 8.35 hours.

The standard deviation of daily viewing time is, σ = 2.5 hours.

The random variable X is Normally distributed.

To compute the probability of a Normal random variable, first we need to compute the raw scores (X) to z-scores (Z).

$z=(x-\mu)/(\sigma)$

(a)

Compute the probability that a household views television between 3 and 9 hours a day as follows:

$P(3<X<9)=P((3-8.35)/(2.5)<(X-\mu)/(\sigma)<(9-8.35)/(2.5))$

$=P(-2.14<Z<0.26)\n=P(Z<0.26)-P(Z<-2.14)\n=0.60257-0.01618\n=0.58639\n\approx0.5864$

Thus, the probability that a household views television between 3 and 9 hours a day is 0.5864.

(b)

Let the viewing hours in the top 2% be denoted by x.

Then,

P (X > x) = 0.02

⇒ P (X < x) = 1 - 0.02

P (X < x) = 0.98

⇒ P (Z < z) = 0.98

The value of z for the above probability is:

z = 2.054

*Use a z-table for the value.

Compute the value of x as follows:

$z=(x-\mu)/(\sigma)\n2.054=(x-8.35)/(2.5)\nx=8.35+(2.054* 2.5)\nx=13.485\nx\approx13.49$

Thus, the viewing hours in the top 2% is 13.49 hours.

(c)

Compute the probability that a household views television more than 5 hours a day as follows:

$P(X>5)=P((X-\mu)/(\sigma)>(5-8.35)/(2.5))$

$=P(Z>-1.34)\n=P(Z<1.34)\n=0.90988\n\approx0.9099$

Thus, the probability that a household views television more than 5 hours a day is 0.9099.

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