MATHEMATICS HIGH SCHOOL

What is the length of the third side of the window frame below?A. 10 inches
B. 12 units
C. 16 units
D. 20 units
What is the length of the third side of the - 1

Answers

Answer 1
Answer:

Answer:

20 units

Step-by-step explanation:

a^(2)+b^(2)=c^(2)

48^(2)+b^(2)=52^(2)

2304+b^(2)=2704

2304-2304+b^(2)=2704-2304

b^(2)=400

\sqrt(b^(2))=\sqrt(400)

b=20

therefore,20 is the length of the unknown side

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Answers

Answer:

Step-by-step explanation:

ok weirdo

There are 50 numbers. Each number is subtracted from 53 and the mean of the numbersso obtained is found to be – 3.5. Determine the mean of the given numbers.

Answers

Hello,

x_(1) , x_(2) , x_(3) , ... x_(50) \n\n \overline{x}= (\sum_(i=1)^(50)\ x_(i))/(50) \n\n (\sum_(i=1)^(50)\ 53-x_(i) )/(50) =-3.5\n (50*53 )/(50) -(\sum_(i=1)^(50)\ x_(i))/(50)=-3.5\n\n 53-\overline{x}=-3.5\n \overline{x}=53+3.5=56.5\n

What are the solutions to the equation? x2 + 6x = 40

Answers

x² + 6x = 40

Subtract 40 from  both sides:

x² + 6x - 40 = 40 - 40

refine: x² + 6x - 40 = 0

factor x² + 6x - 40 = 0

( x- 4 ) ( x + 10 ) = 0

solve x - 4 = 0

x = 0 + 4

x = 4

solve x + 10 = 0

x = 0 - 10

x = - 10

solution : x = 4 , x = - 10

hope this helps!

Answer:

x_1= 4\nx_2=-10

Step-by-step explanation:

x^2+6x=40

Since it is an equation squared to find the two values of x we can apply the formula of the solver

x = \frac {-b \pm \sqrt {b^2 - 4ac}}{2a}

we equate the equation to zero to be able to apply the solver

x^2+6x=40\nx^2+6x-40=0

a=1 \nb=6\nc=-40

x = \frac {-6 \pm \sqrt {(6)^2 - 4(1)(-40)}}{2(1)}\nx = \frac {-6 \pm \sqrt {36+160}}{2}\nx = \frac {-6 \pm \sqrt {196}}{2}\nx = \frac {-6 \pm \ 14}{2}\nx_1=  \frac {-6 +\ 14}{2}\nx_1= (8)/(2)= 4\nx_2=\frac {-6 - 14}{2}\nx_2=(-20)/(2)= -10

x_1= 4\nx_2=-10

I NEED HELP ASAP (A new pizza shop opened up and started out$5,344.46 in the hole. Their first month being open they sold 61 pizzas ($3.06 profit each) and 89 sodas ($1.42 profit each). Thier bills for the first month were $1,208.01. How much money do they still need to make to break even?

Answers

Answer:

$894.97 is needed more to break even

Step-by-step explanation:

In this question, we want to know how much money the pizza shop need so that their profits will equal their expenses.

Let’s calculate their profit

This can be calculated from the pizza sales

That would be;

61(3.06) + 89(1.42) = $186.66 + $126.38 = $313.04

Now, given that their bills for the first month is $1,208.01, the amount still needed to break even would be the amount of their bills minus the profit made from selling soda and pizza

That would be 1,208.01 - 313.04 = $894.97

Ali and Kiana buried a treasure together on their school's field. The actual field is 400 feet wide. Ali made an 8-inch-wide map to record its location. Kiana made her map using a scale of 1 in. To 20 ft. On Kiana's map, the treasure is 2 inches from the south edge of the field. How far is the treasure from the south edge on Ali's map?

Answers

Answer:

The treasure is 0.8 inches from the south edge on Ali's map.

Step-by-step explanation:

Scaling factor, f = (Original length)/(Scalet length)...(i)

Let f_1 and f_2 be the scaling factors used by Ali and Kiana respectively.

Given that the field is 400 feet= 400x12 inches wide and Ali made an 8-inch-wide map to record its location.

So, f_1 = (400*12)/8=600...(ii)

Kiana made her map using a scale of 1-inch to 20 feet=20x12 inches.

So, f_2=(20*12)/1=240...(iii)

As on Kiana's map, the treasure is 2 inches from the south edge of the field,

so, from equations (i), and (ii), the original length of the treasure for the south edge of the field

=2* f_2

=2x240

=480 inches

Now, again from the equation (i) and (ii), the scaled length of the treasure on Ali's map

= 480/f_1

=480/600

=0.8 inches

Hence, the treasure is 0.8 inches from the south edge on Ali's map.

If the angles of a triangle are 10 45 and 23 what is the perimerter of the triangle

Answers

Answer:

No Solutions

Step-by-step explanation:

In a triangle, the sum of the angles has to be 180 degrees. It also is impossible to find the length of sides without at least one side, since the range of lengths is practically infinite. There are no solutions to this problem.
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