Step-by-step explanation:
Here, the total length of fencing available = 390 yd
Let L = length of the side parallel to river
W = width of other 3 sides.
So, total fencing L + 3 W = 390 yd
or, L = 390 - 3 W
Now, Area of the field = L x W
= (390 - 3 w) (W)
or, A = -3 W² + 330 W
The maximum value of above function is at W =
So, W = 55 yards
Now, L = (390 - 3 (55) ) = 165 yards
Now, maximized area = L x W
= 55 x 165 = 9075 sq yds
Partial fractions are used in numerous aspects of everyday life, especially in fields requiring mathematical calculations. This includes engineering, calculus, computer science, signal processing, and electrical circuits. While we may not directly observe their use, their applications make many of our daily operations possible.
The concept of partial fractions is widely used in numerous aspects of our daily life, especially in fields that require mathematical calculations. Partial fractions make complex mathematical processes simpler and easier to solve.
For instance, in the field of engineering, partial fractions are used to simplify complex fractions in control system design, particularly in Laplace Transform. Moreover, it's also used in calculus to integrate rational functions.
In the realm of computer science, partial fractions can assist with algorithm efficiency when dealing with fractions or rational numbers. They are also used in signal processing and electrical circuits, which are a major part of our daily life as most electronics operate on these principles.
In everyday life, the use of partial fractions might not be directly observed but their applications in various fields make many of our daily life operations and technologies possible.
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$1.43 is equal to £1
so...
1.43*56 would be $80.84
this would be around...$7.98 in US currency
Answer:
s = 260 - g/2
Step-by-step explanation:
Given the following :
Maximum weight swing can hold = 500 pounds
Let suspect's weight = s
George's weight = g
To reach maximum weight :
Double weight of suspect + (George's weight - 20)
Hence, equation:
2s + (g - 20) = 500
2s + g - 20 = 500
2s + g = 500 + 20
2s + g = 520
2s = 520 - g
Divide through by 2
s = 260 - g/2
The question can be represented by the equation 2S + G - 20 = 500, where S is the suspect's weight and G is George's weight. To solve for the suspect's weight, we need to know George's weight.
The question asks for an equation to determine the weight of the suspect based on given conditions. We can express the condition as a mathematical equation. If we let S be the weight of the suspect and G be the weight of George, the information gives us the equation 2S + G - 20 = 500. To solve for the suspect's weight, we will need the weight of George. Without this, there are an infinite number of solutions for S. However, if we were given George's weight, we could subtract 20 from it, subtract that value from 500, and then divide by 2 to get the suspect's weight. As an example, if George weighed 220 pounds, the suspect would weigh (500 - (220 - 20)) / 2 = 150 pounds.
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