Answer:
The answer is ""
Step-by-step explanation:
If the function is:
points are:
use the mean value theorem:
The Mean Value Theorem states that for a continuous and differentiable function on a closed interval, there exists at least one 'c' within that interval where the average change rate equals the instantaneous rate at 'c'. In the given case of interval [-2,2], to find 'c', first calculate the average slope between the points (f(2)-f(-2))/4. Then equate this average slope to the derivative 'f'(c). The solution(s) to this equation are the c values for this problem.
The subject of this question pertains to the Mean Value Theorem in Calculus. According to this theorem, if a function f is continuous on a closed interval [a, b] and differentiable on the open interval (a, b), then there exists at least one number c in the open interval (a, b) such that the average rate of change over the interval equals the instantaneous rate of change at c.
In the given case, we're trying to find the 'c' value for the interval [-2,2]. First, we need to find the average slope between the two points. Assuming f is your function, that would be (f(2)-f(-2))/ (2 - -2). Subtract the function values of the two points and divide by the total interval length. Next, we need to see where this average slope equals the instantaneous slope 'f'(c), this entails solving the equation 'f'(c) = (f(2)-f(-2))/4. The solution to this equation will be the c values that satisfy the Mean value theorem within the provided interval.
#SPJ3
Answer:
45 minutes, hope this helps
Step-by-step explanation:
Answer:
45 minutes.
Step-by-step explanation:
Set up a ratio.
6 keychains: 30 minutes
divide both sides of the ratio by 6
1 keychain: 5 minutes
multiply both sides of the ratio by 9
9 keychains: 45 minutes
It will take him 45 minutes.
I believe the answer is x ≤ -60.
How do I prove this with the double angle law
3=c/-11
a.33
b.-33
c.-14
d.14
19+(22 - 16) =
Answer:
the answer is 25.
Step-by-step explanation:
hope this helps
The exact solutions are x=
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Answer:
Ignore the A before the ±, it wouldn't let me type it correctly.
Step-by-step explanation:
3x + 4 = 1 ÷ x
3x + 4 - 4 = 1 ÷ x - 4
3x = 1 ÷ x - 4
x · 3x = - 4x + 1
3x² = - 4x + 1
3x² - (- 4x + 1) = 0
3x² + 4x - 1 = 0
Ignore the A before the ±, it wouldn't let me type it correctly.
a = 3
b = 4
c = - 1
Two separate equations