MATHEMATICS HIGH SCHOOL

Solve for x in the equation X^2+2x+ 1 = 17x=-1+ V15
x=-17 17
X=-2+25
x=-12 13
Solve for x in the equation X^2+2x+ 1 = 17 - 1

Answers

Answer 1
Answer:

Answer:

it would be the last answer

Step-by-step explanation:

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It costs $20 for each metre ofborder edge for a rectangular area.
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Simplify -(-2a + 13) + (-9a - 2) - (-7a - 3).12
-12
14a - 12
14a - (-12)

Answers

Hi there

-(-2a+13)+(-9-2)-(-7a-3)

-(-2a+13)-9a-2-(-7a-3)

Distribute the negative sign

-(-2a+13)-9a-2+-1(-7a-3)

-(-2a+13)+-9a+-2+-1(-7a)+(-1)(-3)

-(-2a+13)+-9a+-2+7a+3

Distribute

2a+-13+-9a+-2+7a+3

Combine like terms

2a+-13+-9a+-2+7a+3

(2a+-9a+7a)+(-13+-2+3)

=-12

Any questions ?


I hope that's help !


Answer:

-12

Step-by-step explanation:

Is the equation equal to, greater than, or less than the dividend?

12 divided by 1/4

Answers

Greater I’m pretty sure

What is if g(x,y,z) = x + y and S is the first octant portion of the plane 2x + 3y + z = 6 ?

Answers

The question asks for the value of I=\int\int_Sx+y\textrm{ }dS where S=\{(x,y,z)\mid2x+3z+y=6,x\ge0,y\ge0,z\ge0\}.

First let's look at what that surface looks like.

Letting y=z=0 yields x=3
Letting x=z=0 yields y=2
Letting x=y=0 yields z=6

Therefore S is the area of the triangle defined by the three points (3,0,0),(0,2,0),(0,0,6).

We can thus reformulate the integral as I=\int_(z=0)^6\int_(x=0)^(6-z)x+ydxdz.

By definition on the plane y=\frac{6-2x-z}3 thus I=\int_(z=0)^6\int_(x=0)^(6-z)x+\frac{6-2x-z}3dxdz=\int_(z=0)^6\int_(x=0)^(6-z)2+\frac x3-\frac z3 dxdz

I=\int_(z=0)^6\left[2x+\frac{x^2}6-\frac{zx}3\right]_(x=0)^(6-z)dz=\int_(z=0)^62(6-z)+\frac{(6-z)^2}6-\frac{z(6-z)}3\right]dz

I=\int_(z=0)^6\frac{z^2}2-6z+18=\left[\frac{z^ 3}6-3z^2+18z\right]_(z=0)^6=36-108+108

Hence \boxed{I=\int\int_Sx+y\textrm{ }dS=36}

For which system of equations is (2, 2) a solution? A.–3x + 3y = 0
x + 6y = 10B.–2x + 5y = –6
4x – 2y = 4C.5x – 2y = –6
3x – 4y = 2D.2x + 3y = 10
4x + 5y = 18

Answers

A.)\n\n-3x + 3y = 0\nx + 6y = 10 \ / *3\n\n-3x + 3y = 0\n3x + 18y = 30\n+------\n21y =30 \ / :21\n \ny=(30)/(21)=(10)/(7)\n\nnot \ true


B.)\n\n-2x + 5y = -6 \ / \cdot 2\n4x - 2y = 4\n \n-4x + 10y = -12 \n4x - 2y = 4 \n+-------- \n8y=-8\ /:8\n \ny=-1\n \n not \ true


C.\n\n5x - 2y = -6 \ / \cdot 2\n3x - 4y = 2 \n \n 10x - 4y = -12 \n 3x- 4y = 2\n+------\n13x=-11 \ / :13\n \nx=-(11)/(13)\n\n not \ true


D.)\n\n2x + 3y = 10\ / \cdot (-2)\n4x + 5y = 18\n\n-4x -6y =-20\n4x + 5y = 18\n+-------\n-y = -2 \ / \cdot (-1)\n \ny=2

2x + 3*2 = 10\n \n2x=10-6 \n \n2x=4 \ / :2 \n \n x=2 \n \n true
x=2\ \ \ and\ \ \ y=2\n\nA.\ \ \ \ \ \ x + 6y = 2+6\cdot2=2+12=14 \neq 10\n\nB.\ \ \ \ \ -2x + 5y =-2\cdot2+5\cdot2=-4+10=6 \neq -6\n\nC.\ \ \ \ \ \ \ 5x-2y =5\cdot2-2\cdot2=10-4=6 \neq -6\n\nD.\ \ \ \ \ \ \ 2x + 3y =2\cdot2+3\cdot2=4+3= 10\nand\ \ \ \ \ \ 4x + 5y = 4\cdot2+5\cdot2=8+10=18\n\nAns.\ (2,\ 2)\ is\ a\ solution\ for\ system \ D

Simplify this expression: 19 – (–8) – (–14) = ?
A. 41
B. –7
C. –3
D. 25

Answers

When you are subtracting a negative, you treat it as if you are adding a positive. So 19-(-8) would be 19 + 8 which is 27. Then do the same thing with the 14, so instead of 27 -(-14) it's 27 + 14 which is 41. So your answer is 41. I hope this helps! XD
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