4. Which of the following best describes Kinetic Energy?Stored energy due to position
Energy of motion
Force applied over a distance
A push or pull exerted on an object

Answers

Answer 1
Answer:

Answer:

Energy Of Motion

Explanation:


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What is the density of water?
gram/mL
(fill in the number)

Answers

Answer:

1.00 gram per milliliter (1 g/mL). In other words, 1 milliliter of water has a mass of 1 gram. A drop of water is 0.05 mL of water, so its mass would be 0.05 grams.

Explanation:

The city police are in pursuit of Robin Banks after his recent holdup at the savings and loan. The high-speed police chase ends at an intersection as a 2080-kg Ford Explorer (driven by Robin) traveling north at 22.6 m/s collides with a 18400-kg garbage truck moving east at 10.4 m/s. The Explorer and the garbage truck entangle together in the middle of the intersection and move as a single object. Determine the post-collision speed and direction of the two entangled vehicles.

Answers

Answer:

v=9.6215m/s\n\theta=13.8^o

Explanation:

This problem is an example of a perfectly inelastic collision. After the collision, the two cars merge into a single object. So in order to find the velocity of that object, we need to find the velocity of the center of mass of the given system of 2 cars.

Mass of Ford = m_F = 2080 kg

Mass of truck = m_T = 18400 kg

Velocity of Ford = v_F = 22.6 m/s north

Velocity of truck = v_T = 10.4 m/s east

Let us break up the velocity vector into 2 components, one along north (v_N) and one along east (v_E).

Therefore,

v_N=(m_Fv_F_(north)+m_Tv_T_(north))/(m_F+m_T) =((2080*22.6)+(18400*0))/(2080+18400) =2.2953m/s

(speed of truck along the north is zero)

Similarly,

v_E=(m_Fv_F_(east)+m_Tv_T_(east))/(m_F+m_T) =((2080*0)+(18400*10.4))/(2080+18400) =9.3437m/s

(speed of Ford along the east is zero)    

Hence, the resultant speed of the entangled cars is given by,

v=√(v_N^2+v_E^2) =√(2.2953^2+9.3437^2)m/s=9.6215 m/s

and the direction is given by (please refer to the figure attached),

\theta=tan^(-1)((v_N)/(v_E) )=tan^(-1)((2.2953)/(9.3437) )=13.8^o

Final answer:

The post-collision speed and direction of the two entangled vehicles, calculated using principles of momentum conservation and trigonometry, are found to be 9.82 m/s and 76.4 degrees east of north respectively.

Explanation:

In this scenario, we are dealing with the principles of momentum conservation. In a collision like this one, the total momentum before the collision equals the total momentum after the collision, as long as no external forces are acting on the system. The momentum (p) of an object is calculated as the mass (m) of the object multiplied by its velocity (v), or p=mv.

Before the collision, the total momentum of the system (ptotal) is the sum of the momentum of the Ford Explorer (pExplorer) and the garbage truck (ptruck). After the collision, they move together as a single object, so their combined mass and velocity would make up the total momentum.

Based on the given information, pExplorer = 2080 kg * 22.6 m/s = 47,008 kg*m/s and ptruck = 18400 kg * 10.4 m/s = 191,360 kg*m/s. The direction should also be taken into account. Since they are perpendicular to each other, we can use the Pythagorean Theorem to find the resultant momentum: (pExplorer)^2 + (ptruck)^2 = ptotal^2, which gives a total momentum of 201,262.8 kg*m/s.

Now, the total mass (mtotal) of two entangled vehicles is 2080 kg + 18400 kg = 20480 kg. Hence the velocity (v) of the two vehicles after the collision is calulated by ptotal divided by mtotal : 201262.8 kg*m/s / 20480 kg = 9.82 m/s. The direction is calculated using trigonometrics such as tan(-1)(ptruck / pExplorer) which gives a direction of 76.4 degrees east of north.

Learn more about Momentum Conservation here:

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A rock at the top of a 30 meter cliff has a mass of 25 kg. Calculate the rock’s gravitational potential energy when dropped off the cliff. Assuming that energy is conserved and there is no air friction and gravity is 9.8 m/sec., at the bottom of the cliff the rock’s potential energy is completely converted to kinetic energy. Use the formula for kinetic energy to calculate the rock’s speed at the bottom of the cliff. Show all calculations.

Answers


Potential energy =

                     (mass) x (gravity) x (height above the reference level) .

Relative to the bottom of the cliff, the potential energy
at the top of the cliff is

                         (25kg) x (9.8 m/s²) x (30 meters)

                     =  (25 x 9.8 x 30)  kg-m²/s²

                     =        7,350 joules .

Kinetic energy = (1/2) x (mass) x (speed²)

The rock's kinetic energy at the bottom is
the same as its potential energy at the top.

                                        7,350 joules = (1/2) x (25 kg) x (speed²)

Divide each side
by 12.5kg :                7,350 joules/12.5 kg  =  speed²

                                 7,350 kg-m²/s² / 12.5kg  =  speed²

                                 (7,350 / 12.5)  m²/s²  =  speed²

                                      588 m²/s²  =  speed²
Take the square root
of each side:            
                                   Speed = √(588 m²/s²) 

                                             =  24.248... m/s       (rounded)

Lets see:-

We have our formula for potential energy, which we are trying to solve for, 

PE = mgh  or  potential energy = mass * gravity * height

So we know that PE all depends on these. 

Height :  30 meters
Mass : 25 kg
Gravity (which is always constant) : 9.8 m/s/s

Now add into formula. 

PE = 25*30*9.8 
PE = 7350 Joules

Answer: PE = 7350 Joules

What environmental factors affect kinetic energy and diffusion? 

Answers

There are several environmental factors that affect the kinetic energy and diffusion. The environmental factors are temperature, molecular size, and pressure, nature of the material and the concentration of the material. All the mentioned factors directly impact the kinetic energy and diffusion of a material or compound or fluid. Temperature can generally increase the kinetic energy of molecules within a compound or a substance. Increase or decrease of temperature changes the shape and nature of the material concerned. So these natural factors have a big influence on the kinetic energy and diffusion.



Answers
Temparature
Humidity (Amount of molecules in the air)


Explanation
Examples of environmental factors are, temperature, wind, pressure, humidity etc. Kinetic energy is the energy possessed by a body in motion. 
This motion can be affected by factors such as rain and humidity since the make the medium more dense. It require more energy to move in a denser medium. 
Diffusion is the movement of molecules from a region of high concentration to a region of low concentration. When temperatures are high the molecules get more energy and move more faster increasing the rate of diffusion.  

A 70.0 kg man jumping from a window lands in an elevated fire rescue net 11.0 m below the window. He momentarily stops when he has stretched the net by 1.50 m. Assuming that mechanical energy is conserved during this process and that the net functions like an ideal spring, find the elastic potential energy of the net when it is stretched by 1.50 m. (10 pts)

Answers

Answer:

70.15 Joule

Explanation:

mass of man, m = 70 kg

intial length, l = 11 m

extension, Δl = 1.5 m

Let K is the spring constant.

In the equilibrium position

mg = K l

70 x 9.8 = K x 11

K = 62.36 N/m

Potential energy stored, U = 0.5 x K x Δl²

U = 0.5 x 62.36 x 1.5 x 1.5

U = 70.15 Joule

The temperature of a system must increase when heat energy is added true or false?

Answers

False.

In fact, the temperature T of a system is directly proportional to the internal energy U of the system, and the first law of thermodynamics states that the variation of internal energy of a system is given by
\Delta U = Q-W
where 
Q is the heat added to the system
W is the work done by the system on the surroundings

We see from the formula that we have 2 possible cases:
1) the heat added to the system (Q) is greater than the work done by the system (W) --> \Delta U is positive, this means that the temperature of the system increases
2) the heat added to the system (Q) is less than the work done by the system (W) --> \Delta U is negative, this means that the temperature of the system decreases

Therefore, it's not true that when heat is added to the system, its temperature must increase: it depends on the value of the work done, W. So, the original statement is false.