Answer:
The average depth of the ocean is about 12,100 feet.
Explanation:
An object with greater charge will exert a greater force on an object than an object with smaller charge would. However, if you consider two charges that exert a force on each other, regardless of the magnitude of charge, both charges will exert an equal force on each other because of Newton's third law.
The baseball is thrown at 50 m/s and the softball is thrown at 25 m/s.
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During a race, a horse's speed increases from 65 m/s to 73 m/s during the last 5.0 seconds of that race, 1.60 m/s² was the rate of acceleration during this time.
The rate of change of velocity is defined as acceleration. Acceleration usually indicates that the speed is changing, but this is not always the case. When an object moves in a circular path at a constant speed, it is still accelerating because its velocity direction changes.
Acceleration occurs when the speed of an object increases or decreases, or when it changes direction. Acceleration, like velocity, has two types: average and instantaneous.
a = v - v₀ / t
Then, a = 73 × 65 / 5
a = 1.60 m/s²
Thus, 1.60 m/s² was the rate of acceleration during this time.
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Answer:
1.6m/s²
Explanation:
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The object of mass with 6.3 Kg will have an acceleration of 1.12 m/s² if a force of 7.1 Newtons is applied.
Force is an external agent acting on a body to change its motion or to deform it. There are various kinds of forces such as gravitational force, magnetic force, nuclear force etc.
Acceleration is a physical quantity that measures the rate of change in velocity of a body. Like force, it is a vector quantity. As per Newton's second law of motion, force is the product of mass and acceleration.
Hence, F = m a
given that, m = 6.3 Kg
F = 7.1 N.
then a = F/m
a = 7.1 N/6.3 kg
= 1.12 m/s²
Therefore, the acceleration of the object is 1.12 m/s².
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Answer:
F=ma
7.1=6.3×m
7.1÷6.3=m
m=1.126 kg
Explanation:
To determine which force does more work, we can calculate the work done by each force using the formula:
Work = Force × Distance
For the first scenario:
Work = 500 N × 10 m = 5000 N·m
For the second scenario:
Work = 100 N × 40 m = 4000 N·m
Therefore, the force of 500 N moving through 10 m does more work, with a total of 5000 N·m.