Answer:
t=(a+by)/(y-1)
Step-by-step explanation:
(t-b)y =t+a
ty-by = t+a
ty-by=t+a
ty-by=a+by
t(y-1)=a+by
thus,
t=(a+by)/(y-1)
Answer:
D.SSS Congruence is correct
Without more information, any of ASA, SAS or SSS could potentially prove that △ABC ≅ △BAD. AAA cannot, since it proves only similarity, not congruence.
To determine whether the triangles △ABC and △BAD are congruent, we would need to apply one of the known congruence theorems. This could be the ASA Congruence theorem, the SAS Congruence theorem, or the SSS Congruence theorem.
The AAA Congruence theorem, however, cannot be used to prove triangle congruence. It is important to highlight that it only proves similarity, not congruence.
From the given options, we need to know the exact measures of the angles and sides for △ABC and △BAD to choose the correct theorem to apply. Without any additional information, any of the options ASA, SAS, or SSS could potentially be used.
#SPJ11
in standard form find the center and radius of the circle.show all of your work for full credit
The given equation can be rewritten into the form of an equation for a circle with center (h,k) and radius r. After completing the squares for x and y coefficients, we determine the center as (2, -5/2) and radius as 1.
The provided equation is 2x2 + 2y2 - 8x + 10y + 2 = 0.Let's rewrite it in the form of an equation for a circle, which is (x-h)^2 + (y-k)^2 = r^2, where (h,k) represents the center of the circle and r represents the radius:
First, we group the terms related to x and y separately like this: 2(x2- 4x) + 2(y2 + 5y) +2 = 0.
Now, re-arrange the terms to complete the square: 2[(x-2)^2 - 4] + 2[(y+5/2)^2 - (5/2)^2] + 2 = 0.
Re-arrange again, this time to make it equate to zero: (x-2)^2 + (y+5/2)^2 = 1. Hence, the circle's center (h,k) is at (2, -5/2) and the radius (r) is the square root of 1, which is 1.
#SPJ2
Answer:
first group x's with x's and y's with y's
then complete the squra with x's and y's
2x^2-8x+2y^2+10y+2=0
2(x^2-4x)+2(y^2+5y)+2=0
take 1/2 of linear coeficient and square
-4/2=-2, (-2)^2=4
5/2=2.5, 2.5^2=6.25
add that and negative inside
2(x^2-4x+4-4)+2(y^2+5y+6.25-6.25)+2=0
factor perfect squares
2((x-2)^2-4)+2((y+2.5)^2-6.25)+2=0
distribute
2(x-2)^2-8+2(y+2.5)^2-12.5+2=0
2(x-2)^2+2(y+2.5)^2-18.5=0
add 18.5 both sides
2(x-2)^2+2(y+2.5)^2=18.5
divide both sides by 2
(x-2)^2+(y+2.5)^2=9.25
that is a circle center (2,-2.5) with radius √9.25
Answer:
1. 16
2. .....
..............
2. Times
3. Weather
4. location
5. appearance of someone
6. attitude
7. age
8. emotional state of a person (happy sad angry)
part B
write a description of a person or a place IN SPANISH. Use the imperfect form when appropriate.