Help please i’ve been stuck for over an hour
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Answer:
A
Step-by-step explanation:
Look at the -15 first. One factor contains the number 3, so the other one is -15/3 = -5. So, we can cross out B, C and D.
(n - 5)(n - 4) = 0
(n - 5)(n + 4) = 0
(n + 5)(n - 4) = 0
(n + 5)(n + 4) = 0
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Answer:
Factors are (n + 5)(n - 4) = 0.
Step-by-step explanation:
Given : The sum of the squares of 2 consecutive negative integers is 41. What are the numbers.
To find : Which of the following equations is the result of using the factoring method to solve the problem.
Solution : We have given statement
Let two consecutive number are : n and n +1 .
Square of two consecutive number are : n² and (n+1)².
According to question : sum of the squares of 2 consecutive negative integers is 41.
n² + (n+1)² = 41.
n² + n² + 1 +2n =41
2n² + 2n +1 =41
On subtracting 41 from both sides
2n² + 2n +1- 41 = 0
2n² + 2n - 40 = 0
On dividing by 2 to whole equation
n² + n - 20 = 0
On factoring
n² + 5n -4n - 20 = 0
Taking common n from first two terms and -4 from first two last terms
n (n +5) -4 (n +5) = 0
Grouping
(n -4) (n +5) = 0.
Therefore, Factors are (n + 5)(n - 4) = 0.
n^2 + (n+1)^2 = 41
n^2 + n^2 + 2n + 1 = 41
2n^2 + 2n -40 = 0
n^2 + n -20 = 0
(n + 5)(n- 4) = 0
Then the answer is the third option.
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Answer: 0.500
You can find the answer when you use a number line.
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y = 2|3(x - 1)| - 4
y = 6|x - 1| - 4
The graph is a V shaped graph with vertex at (1, -4), x-intercepts at (1/3, 0) and (5/3, 0) any y intercept at (0, 2).
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The sequence is:
3²,x,3^8,3^16
==>x=3^4=81