A researcher wanted to determine the prevalence of type 2 diabetes among persons living with HIV in Ojai, a small town in California. He developed a survey questionnaire and mailed to 600 residents of Ojai. The survey asked participants several questions including whether their doctor or health care professional ever told them that they had diabetes. All 600 residents completed the survey and the researcher considered their sample a random sample of the 2,500 total residents of 3 Ojai. The following data was compiled from the survey. The prevalence of diabetes in the sampled survey was 6%. The researcher wanted to compare the prevalence of diabetes by smoking status. In their survey, they found that among 230, who were smokers, 157 reported diabetes and among the remaining nonsmokers, 50 reported diabetes. Construct a two by two table using the data given above. Be sure to label the cells and margins.
Diabetes
Yes No
Smoking Yes a b
No с d
Total

Answers

Answer 1

Answer:

Answer:

Step-by-step explanation:

Given that:

There are 600 residents in the survey.

And results gathered identify that among 230 who were smokers, 157 are reported to have diabetes and among the remaining nonsmokers, 50 reported diabetes.

The objective is to construct a two by two table from the given data:

Diabetes

Yes No Total

Smoking

Yes 157 230 - 157

= 73 230

No 50 370 - 50 600 - 230

= 320 = 370

Total 157 + 50 320+ 73

= 207 = 393 600

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What is the y-intercept of a line that has a slope of -3 and passes through point (-5, 4)?О-17
О-11
O-7
O-19

Answers

Answer:

0, -11

Step-by-step explanation:

y-4=-3(x-(-5))

y-4=-3x-15

y=-3x-15+4

y=-3x-11 the ordered to the origin is -11

the y-intercept is at the point (0, -11)

Hope this helps

Find the inverse laplace transform of: (2 s + 4) / (s - 3)^3

Answers

Answer:

$e^(3t)(2t+5t^(2))$

Step-by-step explanation:

$L^(-1)[(2s+4)/((s-3)^(3)) ]=$

Using the Translation theorem to transform the s-3 to s, that means multiplying by and change s to s+3

Translation theorem: $L^(1) [F(s-a)=L^(-1)[F(s)|_(s \to s-a)\n L^(1) [F(s-a)=e^(at) f(t)$

$L^(-1)[(2s+4)/((s-3)^(3)) ]=e^(3t) L^(-1)[(2(s+3)+4)/(s^(3)) ]$

Separate the fraction in a sum:

$e^(3t) L^(-1)[(2s+10)/(s^(3)) ]=e^(3t) L^(-1)[(2s)/(s^(3))+(10)/(s^(3)) ]=e^(3t) (L^(-1)[(2)/(s^(2))]+ L^(-1)[(10)/(s^(3))])$

The formula for this is:

$L^(-1)[(n!)/(s^(n+1)) ]=t^(n)$

Modify the expression to match the formula.

$e^(3t) (2L^(-1)[(1)/(s^(1+1))]+ (10)/(2) L^(-1)[(2)/(s^(2+1))])=e^(3t) (2L^(-1)[(1)/(s^(1+1))]+ 5 L^(-1)[(2)/(s^(2+1))])$

Solve

$e^(3t) (2L^(-1)[(1)/(s^(1+1))]+ 5 L^(-1)[(2)/(s^(2+1))])=e^(3t)(2t+5t^(2) )$

Please help me understand I am confused

Answers

9514 1404 393

Explanation:

a) The velocity curve is linearly increasing from 0 to 6 m/s over a period of 2 seconds, then linearly decreasing from 6 m/s to 0 over the same period. The acceleration is the rate of change of velocity, so for the first half of the motion the acceleration is a constant (6 m/s)/(2 s) = 3 m/s². Similarly, over the second half of the motion, the acceleration is a constant (-6 m/s)/(2 s) = -3 m/s².

The distance traveled is the integral of the velocity, so the linearly increasing velocity will cause the distance vs. time curve to have a parabolic shape. The shape will likewise be parabolic, but with decreasing slope, as the velocity ramps down to zero. Overall, the distance versus time curve will have an "S" shape.

The motion (position and velocity) will be continuous, but the acceleration will not be. There will be a significant "j.erk" at the 2-second mark where acceleration abruptly changes from increasing the velocity to braking (decreasing the velocity).

b) The attachment shows the (given) velocity curve in meters per second and its integral, the position curve, in meters.

The integral in the attached works nicely for machine evaluation. For hand evaluation, it is perhaps best written piecewise:

$s(t)=\begin{cases}\displaystyle\int_0^t{3x}\,dx\qquad\text{for $x\le2$}\n\n\displaystyle6+\int_2^t{(12-3x)}\,dx\qquad\text{for $2<x\le4$}\end{cases}$