MATHEMATICS HIGH SCHOOL

7+ (-5)+(-2)=0
7+ (5)+(2)=0
7+(-4)+(-3)=0
7+(-6)+(-1)=0

Answers

Answer 1
Answer:

Answer:

1. true

2. false

3. true

4. true

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karl needs to build a stage that has an area of 72 square feet. the length of the stage should be longer than the width. what are the possible whole number measurements for the length and width of the stage?

Answers

Length could be 9 width could be 8. Because 8 times 9 is 72.
length,width
9,8
12,6
72,1
18,4

Separate 185 into two parts so that one part is 31 more than the other part. Find each part.

Answers

9514 1404 393

Answer:

  108, 77

Step-by-step explanation:

Let x represent the larger part. Then ...

  x + (x -31) = 185

  2x = 216

  x = 108

  x -31 = 77

The two parts are 108 and 77.

at a high school, the probability that a student is a senior is 0.25. the probability that a student plays a sport is 0.20. the probability that a student is a senior and plays a sport is 0.08. what is the probability that a randomly selected student plays a sport, given that the student is a senior?

Answers

Answer:

0.32

Step-by-step explanation:

We have been given that at a high school, the probability that a student is a senior is 0.25. The probability that a student plays a sport is 0.20. The probability that a student is a senior and plays a sport is 0.08.

We will use conditional probability formula to solve our given problem. P(B|A)=\frac{P(\text{A and B)}}{P(A)}, where,

P(B|A) = The probability of event B given event A.

P(\text{A and B)} = The probability of event A and event B.

P(A) =Probability of event A.

Let A be that the student is senior and B be the student plays a sport.  

P(A and B) = Probability that student is a senior and plays a sport.

P(B|A)=\frac{\text{Probability that a student is a senior and plays a sport}}{\text{Probability that a student is senior}}

Upon substituting our given values we will get,

P(B|A)=(0.08)/(0.25)

P(B|A)=0.32

Therefore, the probability that a randomly selected student plays a sport, given that the student is a senior will be 0.32.

Instructions:Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).James bought two T-shirts and one pair of jeans at an online store and paid $40, not including taxes, for his purchase. A month later, the same store sold the T-shirts and jeans at a 50% discount from their original prices. James bought two T-shirts and five pairs of jeans for $60, not including taxes.
Assuming the base prices of the T-shirts and the jeans are the same on both occasions, and ignoring the taxes, the price of a T-shirt is $ and the price of a pair of jeans is $.

Answers

Call T the price of the T-shirts and P de price of the jeans

Initially (without discount)
2T + P = 40

One month later (half prices)
2 (T/2) + 5(P/2) = 60
T +5P/2 = 60

To solve the system of equations multiply the second equation by 2 and substract it from the first equation

   2 T + 5P = 120
- (2 T +   P = 40 )
________________

           4P = 80

P = 80/4
P = 20

From 2T + P = 40

T = (40 - P) / 2 = (40 -20) / 2 = 20/2 = 10.

The price of a T-shirt is $10 and the price of a pair of jeans is $20.

What is the correct classification of 7x2 + 9x + 4? Select one of the options below as your answer:A. monomial B. binomial C. trinomial

Answers

Answer:

The correct classification is trinomial.    

Step-by-step explanation:

Given the equation

7x^2+9x+4

we have to choose the options.

Monomial is an algebraic expression containing one term, binomial with two terms and trinomial with 3 terms.

Now, the given expression

7x^2+9x+4

consisting of 3 terms therefore called trinomial.

Hence, the correct classification is trinomial.
B. binomial

this expression has two terms (whole numbers and a x-term

A skier has decided that on each trip down a slope, she will do 3 more jumps than before. On her first trip she did 5 jumps. Derive the sigma notation that shows how many total jumps she attempts from her third trip down the hill through her tenth trip. Then solve for the number of total jumps from her third to tenth trips.

Answers

Since we are already given the amount of jumps from the first trial, and how much it should be increased by on each succeeding trial, we can already solve for the amount of jumps from the first through tenth trials. Starting from 5 and adding 3 each time, we get: 5 8 (11) 14 17 20 23 26 29 32, with 11 being the third trial.

Having been provided 2 different sigma notations, which I assume are choices to the question, we can substitute the initial value to see if it does match the result of the 3rd trial which we obtained by manual adding.

Let us try it below:

Sigma notation 1:

  10
   Σ (2i + 3)
i = 3

@ i = 3

2(3) + 3
12

The first sigma notation does not have the same result, so we move on to the next.

  10
   Σ (3i + 2)
i = 3

When i = 3; 3(3) + 2 = 11. (OK)

Since the 3rd trial is a match, we test it with the other values for the 4th through 10th trials.

When i = 4; 3(4) + 2 = 14. (OK)
When i = 5; 3(5) + 2 = 17. (OK)
When i = 6; 3(6) + 2 = 20. (OK)
When i = 7; 3(7) + 2 = 23. (OK)
When i = 8; 3(8) + 2 = 26. (OK)
When i = 9; 3(9) + 2 = 29. (OK)
When i = 10; 3(10) + 2 = 32. (OK)

Adding the results from her 3rd through 10th trials: 11 + 14 + 17 + 20 + 23 + 26 + 29 + 32 = 172.

Therefore, the total jumps she had made from her third to tenth trips is 172.

Answer:d

Step-by-step explanation:test
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