The number of degrees in one interior angle of the polygon is 108 degrees.
A polygon is a closed two-dimensional shape having straight line segments. It is not a three-dimensional shape.
Sum of interior angles of a polygon with n sides IS;
Sum of interior angles of a polygon = 540°
Equating both we can determine the number of sides
There are 5 sides in the polygon and the sum of the interior angles of a polygon is 540.
The number of degrees in one interior angle of the polygon is;
Hence, the number of degrees in one interior angle of the polygon is 108 degrees.
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Answer:
66
Step-by-step explanation:
11x6=66
hope it helped
There are 28 students in the larger class.
Let's assume the number of students in one class is x.
Since the other class has 6 more students, the number of students in the other class is x + 6.
The total number of students in both classes is 50.
Therefore, we can write the equation:
x + (x + 6) = 50
2x + 6 = 50
Subtracting 6 from both sides:
2x = 44
Dividing both sides by 2:
x = 22
So, the number of students in the larger class, which is x + 6, is:
22 + 6 = 28
Therefore, there are 28 students in the larger class.
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Value of x = 0 or 1 and value of y = or -1 for the given quadratic equation.
" Quadratic equation is defined as the polynomial whose highest degree of the given variable is equals to 2."
According to the question,
Given equations,
⇒ ____(1)
Quadratic equation,
____(2)
Substitute the value of 'x' from (1) in (2) quadratic equation we get,
⇒
⇒
⇒
⇒
⇒
⇒
⇒
⇒
Substitute in (1) to get the value of 'x' ,
⇒
Hence, value of x = 0 or 1 and value of y = or -1 for the given quadratic equation.
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Answer:
C
Step-by-step explanation:
Let's say the cost of one sandwich is "s" and the cost of one drink is "d". From the first customer's order, we know that 3 sandwiches and 2 drinks cost $14.70. So we can write the equation: 3s + 2d = 14.70 From the second customer's order, we know that 2 sandwiches and 4 drinks cost $13.30. So we can write the equation: 2s + 4d = 13.30 Now, we can solve this system of equations to find the values of "s" and "d". Multiplying the first equation by 2 and the second equation by 3, we get: 6s + 4d = 29.40 6s + 12d = 39.90 Subtracting the first equation from the second equation, we get: 6s + 12d - (6s + 4d) = 39.90 - 29.40 Simplifying, we have: 8d = 10.50 Dividing both sides by 8, we find: d = 1.3125 Now we can substitute this value back into either of the original equations to find the value of "s". Let's use the first equation: 3s + 2(1.3125) = 14.70 Simplifying, we have: 3s + 2.625 = 14.70 Subtracting 2.625 from both sides, we find: 3s = 12.075 Dividing both sides by 3, we get: s = 4.025 So the cost of one sandwich is approximately $4.03 and the cost of one drink is approximately $1.31. Therefore, the correct answer is: c) Sandwich: $4.03, Drink: $1.31
Option (a), with the cost of a sandwich as $3.50 and a drink as $2.35, is the correct solution for this algebraic problem. This conclusion was reached by forming two equations from the information given and solving this system of equations.
This is an algebra problem where we set up two equations to solve for two variables. Let's denote the cost of a sandwich as S and the cost of a drink as D. The first equation derived from the first customer's purchase would be 3S + 2D = 14.70. The second equation from the second customer's purchase would be 2S + 4D = 13.30. To solve these equations, we could multiply the first equation by 2 and the second equation by 3 then subtract the second equation from the first. This will provide the cost of a Sandwich which can then be substituted back into either original equation to get the cost of a Drink. Once you solve this system, the answer appears as option (a): Sandwich $3.50 and Drink $2.35.
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