the sum of the interior angles of a polygon is 540. determine and state the number of degrees in one interior angle of the polygon.

Answers

Answer 1
Answer:

The number of degrees in one interior angle of the polygon is 108 degrees.

What is the polygon?

A polygon is a closed two-dimensional shape having straight line segments. It is not a three-dimensional shape.

Sum of interior angles of a polygon with n sides IS;

\rm  (n-2)* 180

Sum of interior angles of a polygon = 540°

Equating both we can determine the number of sides

\rm  (n-2)* 180=540\n\nn-2=(540)/(180)\n\n n-2=3\n\nn=3+2\n\nn=5

There are 5 sides in the polygon and the sum of the interior angles of a polygon is 540.

The number of degrees in one interior angle of the polygon is;

=(540)/(5)\n\n=108

Hence, the number of degrees in one interior angle of the polygon is 108 degrees.

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Answer 2
Answer: Any polygon with interior angles that add up to 540 must have 5 sides and 5 corners (a pentagon). Assuming it is a regular pentagon, you need to work out what 1/5 of 540 is, which is the same as dividing it by 5. 540/5 = 108. this is the number of degrees in one interior angle of a regular pentagon.

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1 poinA catering assistant mixes 4 parts of cordial to 12 parts of water. Expressthis as a ratio in its simplest form.*1:1/3O 1:2O 1:3O 14

How many sixths are there in 11?

Answers

You can just easily mulltiply six (because (1)/(6)) by 11.

There are 66 sixths in 11.

Answer:

66

Step-by-step explanation:

11x6=66

hope it helped

Two classes have a total of 50 students. One of the classes has 6 more students than the other. How many students are in the larger class.

Answers

Let's say 'x' to number of the students in the smaller class. Since the larger one is 6 more than the smaller one, its number would be 'x+6'. So their sum is equal to 

x+x+6=2x+6 and we know total is 50 so:
2x+6=50\n 2x=50-6\n 2x=44\n x=\frac { 44 }{ 2 } \n x=22 

x is 22 so the larger number 'x+6' is equal to : x+6=22+6=28

There are 28 students in the larger class.

Let's assume the number of students in one class is x.

Since the other class has 6 more students, the number of students in the other class is x + 6.

The total number of students in both classes is 50.

Therefore, we can write the equation:

x + (x + 6) = 50

2x + 6 = 50

Subtracting 6 from both sides:

2x = 44

Dividing both sides by 2:

x = 22

So, the number of students in the larger class, which is x + 6, is:

22 + 6 = 28

Therefore, there are 28 students in the larger class.

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Ellentown College had approximately 3 x 10 to the 3rd power students and Pengrove University has approximately 30,000 students. How many times as much is the number of students at Pengrove University as the number of students at Ellentown College?

Answers

Ellentown has 3000 students, while Pengrove has 30,000. Pengrove has ten times as many students! 

Solve for x and y simultaneously x-2y=3. 3x²-5xy-16y=24

Answers

Value of x = 0 or 1 and value of y = (-3)/(2) or -1 for the given quadratic equation.

What is quadratic equation?

" Quadratic equation is defined as the polynomial whose highest degree of the given variable is equals to 2."

According to the question,

Given equations,

x-2y=3

x=3 + 2y                                ____(1)

Quadratic equation,

3x^(2) -5xy-16y=24                 ____(2)

Substitute the value of 'x' from (1) in (2) quadratic equation we get,

3(3+2y)^(2) -5(3+2y)y-16y=24

3(9+12y+4y^(2) )-5y(3+2y) -16y-24=0

27+36y+12y^(2) -15y-10y^(2) -16y-24=0

2y^(2) +5y+3=0

2y^(2) +2y+3y+3=0

2y(y+1)+3(y+1)=0

(2y+3)(y+1)=0

(2y+3)=0 or (y+1)=0

y=(-3)/(2) or y = -1

Substitute in (1) to get the value of 'x' ,

x= 3+ 2((-3)/(2)) or x = 3 + 2 (-1)

⇒  x = 0 or x = 1

Hence, value of x = 0 or 1 and value of y = (-3)/(2) or -1 for the given quadratic equation.

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x-2y=3                        ⇒y=(x-3)/2
3x²-5xy-16y=24

We can suggest this system of equations by substitution method.
y=(x-3)/2

3x²-5x(x-3)/2-16(x-3)/2=24
least common multiple=2
6x²-5x(x-3)-16(x-3)=48
6x²-5x²+15x-16x+48=48
x²-x=0
x(x-1)=0
Now, we solve two equations:
1)x=0    ⇒y=(0-3)/2=-3/2
2)x-1=0
x=1  ⇒y=(1-3)/2=-1



Answer: we can two solutions:
solution1:  x=0; y=-3/2
solution2:  x=1, y=-1

In a certain café, all sandwiches are priced the same. A customer ordered 3 sandwiches and 2 drinks for $14.70. Another customer bought 2 sandwiches and 4 drinks for $13.30. Find the cost of one sandwich and the cost of one drink, if the cost of each drink is the same price. a) Sandwich: $3.50, Drink: $2.35 b) Sandwich: $2.35, Drink: $3.50 c) Sandwich: $3.25, Drink: $2.10 d) Sandwich: $2.10, Drink: $3.25

Answers

Answer:

C

Step-by-step explanation:

Let's say the cost of one sandwich is "s" and the cost of one drink is "d". From the first customer's order, we know that 3 sandwiches and 2 drinks cost $14.70. So we can write the equation: 3s + 2d = 14.70 From the second customer's order, we know that 2 sandwiches and 4 drinks cost $13.30. So we can write the equation: 2s + 4d = 13.30 Now, we can solve this system of equations to find the values of "s" and "d". Multiplying the first equation by 2 and the second equation by 3, we get: 6s + 4d = 29.40 6s + 12d = 39.90 Subtracting the first equation from the second equation, we get: 6s + 12d - (6s + 4d) = 39.90 - 29.40 Simplifying, we have: 8d = 10.50 Dividing both sides by 8, we find: d = 1.3125 Now we can substitute this value back into either of the original equations to find the value of "s". Let's use the first equation: 3s + 2(1.3125) = 14.70 Simplifying, we have: 3s + 2.625 = 14.70 Subtracting 2.625 from both sides, we find: 3s = 12.075 Dividing both sides by 3, we get: s = 4.025 So the cost of one sandwich is approximately $4.03 and the cost of one drink is approximately $1.31. Therefore, the correct answer is: c) Sandwich: $4.03, Drink: $1.31

Final answer:

Option (a), with the cost of a sandwich as $3.50 and a drink as $2.35, is the correct solution for this algebraic problem. This conclusion was reached by forming two equations from the information given and solving this system of equations.

Explanation:

This is an algebra problem where we set up two equations to solve for two variables. Let's denote the cost of a sandwich as S and the cost of a drink as D. The first equation derived from the first customer's purchase would be 3S + 2D = 14.70. The second equation from the second customer's purchase would be 2S + 4D = 13.30. To solve these equations, we could multiply the first equation by 2 and the second equation by 3 then subtract the second equation from the first. This will provide the cost of a Sandwich which can then be substituted back into either original equation to get the cost of a Drink. Once you solve this system, the answer appears as option (a): Sandwich $3.50 and Drink $2.35.

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Sam is observing the velocity of a car at different times. After three hours, the velocity of the car is 51 km/h. After five hours, the velocity of the car is 59 km/h. Part A: Write an equation in two variables in the standard form that can be used to describe the velocity of the car at different times. Show your work and define the variables used. (5 points) Part B: How can you graph the equation obtained in Part A for the first six hours?

Answers

Assuming that the car is travelling at constant acceleration, follows the equation: v = (v_in) + at where v = velocity v_in = initial velocity, (at t = 0) a = acceleration t = time Given the conditions, v = 51 at t = 3, and v = 59 at t = 5 Eqn 1: 51 = (v_in) + a(3) Eqn 2: 59 = (v_in) + a(5) Solving for v_in and a (using a calculator) v_in = 39 a = 4 therefore the equation for the motion of the car is: v = 39 + 4t This equation can be plotted using excel or wolframalpha.