A compound has a molecular formular of C12H24O6.What is the compound's empirical formula ​

Answers

Answer 1
Answer:

Answer:

We are given the formula of the compound:

C12H24O6

The empirical formula of a molecular formula is the lowest whole number ratio between the number of atoms of each element

The ratio of C to H to O in the given formula is :

12 : 24 : 6

we notice that all 3 of the numbers have 6 in common. Dividing all three of the numbers by 6, we get:

2 : 4 : 1

Hence, the ratio of Carbon to Hydrogen to Oxygen in the empirical formula of the given compound is 2 : 4 : 1 ,

Empirical Formula = C2H4O

Answer 2
Answer:

Answer:

The empirical formula for C12 H24 O6 is C2 H4 O.


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Which of the following best describes the crest of a transverse wave?а. length
b. high point
c. speed
d. low point

Answers

Answer:

B

Explanation:

A chemist titrates 90.0 mL of a 0.5870 M acetic acid (HCH, CO) solution with 0.4794M NaOH solution at 25 °C. Calculate the pH at equivalence. The p Kg of acetic acid is 4.76. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of NaOH solution added

Answers

Answer:

9.09

Explanation:

Please kindly check attachment for the step by step solution of the given problem.

given that the only known ionic charges of lead are pb(ii) and pb(iv), how can you explain the existence of the pb2o3 salt

Answers

Answer:

See Explanation

Explanation:

Pb2O3 is better formulated as PbO.PbO2. It is actually a mixture of the two oxides of lead, lead II oxide and lead IV oxide.

This implies that this compound Pb2O3  (sometimes called lead sesquioxide) is a mixture of the oxides of lead in its two known oxidation states +II and +IV.

Hence Pb2O3  contains PbO and PbO2 units.

The value of delta for the [C_rF_6]^3- complex is 182 kJ/mol. Calculate the expected wavelength of the absorption corresponding to promotion of an electron from the lower-energy to the higher-energy of orbital set in this complex. (Remember to divide by Avogadro's number.) Should the complex absorb in the visible range?

Answers

Answer:  Yes the absorb in the visible range.

Explanation:

The relationship between wavelength and energy of the wave follows the equation:

E=(Nhc)/(\lambda)

where,

E = energy of the wave  = 182 kJ/mol  = 182000 J/mol

N = avogadro's number =  6.023* 10^(23)

h = plank constant = 6.6* 10^(-34)Js^(-1)

c = speed of light = 3* 10^8m/s

\lambda = wavelength of the wave = ?

Putting all the values:

182000=(6.023* 10^(23)* 6.6* 10^(-34)* 3* 10^8m/s)/(\lambda)

\lambda=0.65* 10^(-6)m=650nm    (1nm=10^(-9)m)

The wavelength range for visible rays is 400 nm to 750 nm, thus the complex absorb in the visible range.

Final answer:

The expected wavelength of the absorption in the [CrF6]3- complex cannot be calculated without knowing the exact value of ΔE. Therefore, it is unclear if the complex will absorb in the visible range.

Explanation:

In this complex, the value of delta (Δ) is 182 kJ/mol. To calculate the expected wavelength of the absorption corresponding to the promotion of an electron from the lower-energy orbital to the higher-energy orbital, we can use the equation: Wavelength = (hc)/(ΔE), where h is Planck's constant and c is the speed of light. By substituting the given values and dividing by Avogadro's number, we can calculate the expected wavelength.

However, the information given in the question does not provide the exact value for ΔE. Without this information, it is not possible to calculate the expected wavelength accurately. Therefore, we cannot determine if the complex will absorb in the visible range.

Learn more about Calculating expected wavelength of absorption in a complex here:

brainly.com/question/38332205

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What is the molecular geometry if you have a double bond, a single bond and 1 lone pair around the central atom?

Answers

Answer:

4 pairs are needed for the bonds, leaving 1 lone pair. Each double bond uses 2 bond pairs and can be thought of as a single unit. There are 2 double bond units and 1 lone pair, which will try to get as far apart as possible - taking up a trigonal planar arrangement.

Microwave ovens use microwaves with a wavelength of 0.12 meters. How much energy does this wave have? 2 x 10-20 10 mm FI​

Answers

Answer:

E = 165.75×10⁻²⁶ J

Explanation:

Given data:

Wavelength = 0.12 m

Energy of wave = ?

Solution:

Formula:

E = h c/λ

c = 3×10⁸ m/s

h = 6.63×10⁻³⁴ Js

Now we will put the values in formula.

E = 6.63×10⁻³⁴ Js × 3×10⁸ m/s / 0.12 m

E = 19.89×10⁻²⁶ J.m / 0.12 m

E = 165.75×10⁻²⁶ J