Answer:
x = 14
Step-by-step explanation:
<LOJ = 3x
<KOJ = (2x + 12)°
<LOK = 82°
m<LOJ + m<KOJ = m<LOK (angle addition postulate)
3x + 2x + 12 = 82 (substitution)
5x + 12 = 82
5x = 82 - 12 (Subtraction property of equality)
5x = 70
x = 70/5 (division property of equality)
x = 14
B.5.0m/s
C.10m/s
D.15m/s
The vehicle's acceleration if its value may b assumed to be constant is 10 m/s. Therefore, option C is the correct answer.
Given that, a vehicle designed to operate on a drag strip accelerates from zero to 30m/s while undergoing a straight line path displacement of 45m.
Acceleration is the name we give to any process where the velocity changes. Since velocity is a speed and a direction, there are only two ways for you to accelerate: change your speed or change your direction-or change both.
Here, Δx = 45 m, v₀ = 0 m/s and v = 30 m/s
Using the formula v² = v₀² + 2aΔx
(30 m/s)² = (0 m/s)² + 2b (45 m)
b = 10 m/s
The vehicle's acceleration if its value may b assumed to be constant is 10 m/s. Therefore, option C is the correct answer.
Learn more about the acceleration here:
brainly.com/question/12550364.
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Answer:
C. 10 m/s²
Step-by-step explanation:
Given:
Δx = 45 m
v₀ = 0 m/s
v = 30 m/s
Find: a
v² = v₀² + 2aΔx
(30 m/s)² = (0 m/s)² + 2a (45 m)
a = 10 m/s²
Answer:
(the statement does not appear to be true)
Step-by-step explanation:
I don't think the statement is true, but you CAN compute the intercepted arc from the angle.
Note that BFDG is a convex quadrilateral, so its angles sum to 360. Since we know the inscribed circle touches the angle tangentially, angles BFD and BGD are both right angles, with a measure of 90 degrees.
Therefore, adding the angles together, we have:
alpha + 90 + 90 + <FDG = 360
Therefore, <FDG, the inscribed angle, is 180-alpha (ie, supplementary to alpha)
123456
Pounds Frequency Multiplication
1
4
1
4
4
4
1
1
3
4
3
4
8
8
1
1
4
1
1
4
4
4
Answer:
Part One:
Pounds Frequency Multiplication
1/4 4 1
3/4 8 6
1 1/4 4 5
1 1/2 2 3
Part Two:
The total number of pounds of cheese ordered is 15 pounds
Answer:
Step-by-step explanation:
There are lots of ways we can think about the typical number of cavities.
The most patients had 0cavities.
If we split the cavities evenly, each patient would have 2 or 3 cavities.
If we put our dot plot on a balance scale, it would balance when the pivot was between 2 and 3 cavities.
The scale would tip if, for example, we put the pivot at 5 cavities.
There are 8 patients with 2 cavities each. About half of the rest of the patients have fewer than 2 cavities and about half have more than 2 cavities.
Of the choices, it is reasonable to say that a patient typically had about 2 cavities.
, -Written in
The 'typical' number of cavities one patient had can be determined by finding the mode (most common number) in the data set, which should be represented in the dot plot. To do this, one would count the number of dots at each value on the dot plot. The value with the most dots would be the 'typical' number of cavities.
The question is asking for a 'typical' number of cavities one patient had out of Dr. Vance's 63 patients. In statistics, a typical, or 'common', value can be shown by calculating the mode, which is the number that appears most frequently in a data set.
Unfortunately, the dot plot is missing from the information provided. However, to find the mode (or typical value) using a dot plot, you would typically count how many dots are at each value on the plot. The value with the most dots (indicating the most patients with that number of cavities) is the mode. This would be the 'typical' number of cavities a patient of Dr. Vance had last month.
Let's create a hypothetical scenario. If your dot plot looked like this:
The mode would be 2 cavities because 24 patients had this amount, more than any other amount. Therefore, the 'typical' number of cavities one patient had would be 2.
#SPJ11
Answer:
this makes no sense she can make any bows