Y+z+ 2; use y=-6, and z = 5

Answers

Answer 1

Answer:

When y = -6 and z = 5, the value of the expression y + z + 2 is 1.

To calculate the expression y + z + 2 when y = -6 and z = 5, you simply substitute these values into the expression and perform the arithmetic operations:

y + z + 2 = (-6) + (5) + 2

Now, perform the addition:

(-6) + (5) + 2 = -1 + 2 = 1

So, when y = -6 and z = 5, the value of the expression y + z + 2 is 1.

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Answer 2

Answer:

Answer:

Step-by-step explanation:

y + z + 2

first you have to replace the variables with the numbers

This is your equation now.

-6 + 5 + 2

Now you just have to solve it.

-6 + 5 = -1+ 2 = 1

7 - 6 = 1

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Of the 50 states in the Uinted States, 26 have more than four million people. What fraction of US states states have LESS than four million people?

Answers

Answer:

12 / 25 = fraction. 48% = percent.

Step-by-step explanation:

If 26 states have more than four million people then we would do 50 - 26 = 24 (assuming that a state does not have exactly four million people. That would be 24 / 50 = 12 / 25 if you want to simplify it.

Give step by step answer

Answers

Answer:

Nancy put 3 cups of vegetables in each container.

Step-by-step explanation:

1. Add the amount of vegetables together

2. Divided the number of vegetables by 5, since they are put into 5 separate containers.

____________________________________________________________2+1+2+1+3+6 = 15

15 divided by 5 or 5 x ? = 15

Answer:

2 1/2 cups of vegetables

Step-by-step explanation:

This is an averages question, so add all numbers and divide by amount of numbers

2+1+2+1+3+6=15

15/6=2 1/2

What is the maximum height of the basketball when the player passes the ball to someone? Initially, the ball moves at a speed of 12m/sec at an angle with respect to the horizontal of 45 degrees. Is it possible that other player standing 8m away is able to catch the ball without any bounces?

Answers

Answer with explanation:

Since the motion of the ball is projectile motion we shall use the equations for projectile motion.

The maximum height achieved by the projectile is given by

$h_(max)=(v_(o)^(2)sin^(2)(\theta ))/(2g)$

Applying the values we get

$h_(max)=(12^(2)* sin^(2)(45))/(2* 9.81)\n\nh_(max)=3.669m$

The range of the projectile is given by

$R=(v_(o)^(2)sin(2\theta ))/(2g)$

Applying values we get

$R=(12^(2)* sin(2* 45 ))/(2* 9.81)\n\nR=7.339m$

thus the maximum horizontal distance reached by the ball equals 7.339 meters after which it bounces thus a person standing 8 meters away will not be able to catch it.

(The height of the players is not taken into account since no info is given about their height.)

Convert 32/5 to a mixed number.