MATHEMATICS COLLEGE

Look at the figure. If ∆LMC ≅ ∆BJK, then _____ ≅ ∆KB
A. BJ
B. CM
C. ML
D. CL

Answers

Answer 1
Answer:

If ∆LMC ≅ ∆BJK, then ∆CL ≅ ∆KB. so the correct option is D.

What is the congruent triangle?

Two triangles are said to be congruent if the length of the sides is equal, a measure of the angles are equal and they can be superimposed.

We have been given that ∆LMC ≅ ∆BJK.

The image of the triangles are attached below;

The triangle are congruent to each other so,

∆LMC ≅ ∆BJK

∆LM ≅ ∆BJ

∆LC ≅ ∆BK

∆MC ≅ ∆JK

Thus, ∆LC ≅ ∆BK so the correct option is D.

Learn more about congruenttriangles;

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Answer 2
Answer: The answer to your question is D.CL

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What is the sum of prime numbers between 40 and 56​

Answers

Answer:

184

Step-by-step explanation:

The prime numbers between 40 and 56​ are 41, 43, 47, and 53.

Add the prime numbers.

41 + 43 + 47 + 53

= 184

Answer:

184

Step-by-step explanation:

Prime numbers between 40 and 56: 41, 43, 47, 53.

41+43+47+53=

84+47+53=

131+53=

184

Write an equation in point-slope form for the line through the given point with the given slope.(8, –3); m = -1/4

Answers

Answer:

y+3 = -1/4(x-8)

Step-by-step explanation:

Point slope form is y-y1 = m(x-x1)  where m is the slope and (x1-y1) is a point on the line

(y- -3) =-1/4(x-8)

y+3 = -1/4(x-8)

What is the total interest paid on an $185,000 loan at 6.25% APR over 15 years (monthly payments)? ​

Answers

Answer:

$100,522

Step-by-step explanation:

Answer:

Total Interest $100,522

Step-by-step explanation:

Someone please answer!

Answers

Answer:

m=1/2

Step-by-step explanation:

y1= 1

y2=6

x1= -10

x2-0

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m= y2-y1/x2-x1

m=6-1/0 - - 10

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Hey I need help with my coordinates ​

Answers

Ok send the picture so I can help you.

Answer:

what is the question? I can help

Step-by-step explanation:

Find two unit vectors orthogonal to both given vectors. i j k, 4i k

Answers

The cross product of two vectors gives a third vector \mathbf v that is orthogonal to the first two.

\mathbf v=(\vec i+\vec j+\vec k)*(4\,\vec i+\vec k)=\begin{vmatrix}\vec i&\vec j&\vec k\n1&1&1\n4&0&1\end{vmatrix}=\vec i+3\,\vec j-4\,\vec k

Normalize this vector by dividing it by its norm:

(\mathbf v)/(\|\mathbf v\|)=(\vec i+3\,\vec j-4\,\vec k)/(√(1^2+3^2+(-4)^2))=\frac1{√(26)}(\vec i+3\,\vec j-4\vec k)

To get another vector orthogonal to the first two, you can just change the sign and use -\mathbf v.
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