MATHEMATICS COLLEGE

Solve for e.
9e + 4 = -5e + 14 + 13e

Answers

Answer 1
Answer:

Answer:

e = 10

Step-by-step explanation:

In this problem we are told to solve for e. This means we need to isolate the variable e, leaving it completely by itself on one side of the equation.

9e + 4 = -5e + 14 + 13e

We can do this multiple ways, but I will show you how I would do it.

First I would subtract 4 from both sides.

9e + 4 = -5e + 14 + 13e

9e = -5e + 14 + 13e - 4

We can simplify the right side of the equation down by subtracting four from 14.

9e = -5e + 10 + 13e

Next, let's simplify our algebraic expressions. We can subtract 5e from 13e (or add -5e to 13e whatever tickles your fancy)

-5e + 13e = 8e

9e = 8e + 10

Now we subtract algebraic expression 8e from both sides

9e - 8e = 10

All of our expressions with the variable e are now on one side but we aren't done yet. Compute 9e - 8e.

9e - 8e = 10

1e = 10

or

e = 10

We have isolated e! Our final answer is e = 10

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Perform the following calculation: (+10) + (–45). A. 55 B. –55 C. –35 D. 35

Answers

Answer:

Option C - (+10) + (-45)=-35

Step-by-step explanation:

Given : Expression (+10) + (-45)

To find : Perform the calculation in the given expression ?

Solution :

Step 1 - Write the expression

=(+10) + (-45)

Step 2 - Applying multiplication symbol rule,(+)(-)=(-)

=10-45

Step 3 - Solve the subtraction,

=-35

Therefore, Option C is correct (+10) + (-45)=-35

Suppose that weekly income of migrant workers doing agricultural labor in Florida has a distribution with a mean of $520 and a standard deviation of $90. A researcher randomly selected a sample of 100 migrant workers. What is the probability that sample mean is less than $500

Answers

Answer:

z = (500-520)/((90)/(√(100)))= -2.22

And we can find this probability using the normal standard distribution and we got:

P(z<-2.22) =0.0132

Step-by-step explanation:

For this case we have the foolowing parameters given:

\mu = 520 represent the mean

\sigma =90 represent the standard deviation

n = 100 the sample size selected

And for this case since the sample size is large enough (n>30) we can apply the central limit theorem and the distribution for the sample mean would be given by:

\bar X \sim N(\mu , (\sigma)/(√(n)))

And we want to find this probability:

P(\bar X <500)

We can use the z score formula given by:

z = (500-520)/((90)/(√(100)))= -2.22

And we can find this probability using the normal standard distribution and we got:

P(z<-2.22) =0.0132

The solution to a system of equations is any ordered pair that
makes both equations true/false

Answers

the answer to the question is true

Answer: false

Step-by-step explanation:

Determine the length of UT.

Answers

I think the answer would be 20

Breyers is a major producer of ice cream and would like to test if the average American consumes more than 17 ounces of ice cream per month. A random sample of 25 Americans was found to consume an average of 19 ounces of ice cream last month. The standard deviation for this sample was 5 ounces. Breyers would like to set LaTeX: \alpha = 0.025 α = 0.025 for the hypothesis test. It is known that LaTeX: z_{\alpha}=1.96 z α = 1.96 and LaTeX: t_{\alpha}=2.06 t α = 2.06 for the df = 24. Also, it is established that the ice cream consumption follows the normal distribution in the population. The conclusion for this hypothesis test would be

Answers

Answer:

The conclusion for this hypothesis test would be that the average American consumes less than or equal to 17 ounces of ice cream per month.

Step-by-step explanation:

We are given that Breyers is a major producer of ice cream and would like to test if the average American consumes more than 17 ounces of ice cream per month.

A random sample of 25 Americans was found to consume an average of 19 ounces of ice cream last month. The standard deviation for this sample was 5 ounces.

Let \mu = average ounces of ice cream consumed by American per month

So, Null Hypothesis, H_0 : \mu \leq 17 ounces     {means that the average American consumes less than or equal to 17 ounces of ice cream per month}

Alternate Hypothesis, H_A : \mu > 17 ounces    {means that the average American consumes more than 17 ounces of ice cream per month}

The test statistics that will be used here is One-sample t test statistics as we don't know about population standard deviation;

                                 T.S.  = (\bar X-\mu)/((s)/(√(n) ) )  ~ t_n_-_1

where, \bar X = sample average = 19 ounces

             s = sample standard deviation = 5 ounces

             n = sample of Americans = 25

So, test statistics  =  (19-17)/((5)/(√(25) ) )  ~ t_2_4

                               =  2

The value of the test statistics is 2.

Now at 0.025 significance level, the t table gives critical value of 2.06 at 24 degree of freedom for right-tailed test. Since our test statistics is less than the critical values of t, so we have insufficient evidence to reject our null hypothesis as it will not fall in the rejection region due to which we fail to reject our null hypothesis.

Therefore, we conclude that the the average American consumes less than or equal to 17 ounces of ice cream per month.

How many seats are in theatre

Answers

When we solve the equation, we find that there are 26 seats in the theatre. Option C

How do we form and solve an equation from the given scenario?

We will consider the number of seats in the theatre as x.

The total cost of renting the theatre and the seats is $520 for the rental plus $30 × the number of seats should be expressed as 30x.

If every seat is sold, the total income from selling the tickets would be $50 × the number of seats is expressed as (50x)

The equation becomes

520 + 30x = 50x

520 = 50x - 30x

520 = 20x

x = 520/20

x = 26

Find more exercises on equations;

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