Bill is in a class of 15 boys and 35 girls. 40% of the students in the class take the bus to school. How many students do not take the bus to school?
Answers
Answer:
30 students not take bus to school .
Step-by-step explanation:
As given
Bill is in a class of 15 boys and 35 girls.
Total number of students in the class = Number of boys + Number of girls
= 15 + 35
= 50
As given
40% of the students in the class take the bus to school.
40% is written in the decimal form.
= 0.40
Number of students take bus to school = 0.40 × Total students in class.
= 0.40 × 50
= 20
Thus
Students not take bus to school = Total students - Number of students take bus to school
= 50 - 20
= 30
Therefore 30 students not take bus to school .
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What expression is equvialent to -6 (-2/3 + 2x)?
Answers
16.9 + 12.1 = 29
16.9 - 12.1 = 4.8
When you subtract it mentally you'd get 4.8
A.30
B.18
C.15
D.10
Answers
3 = 1 x 3
5 = 1 x 5
10 = 2 x 5
Lets Multiply it:
We already have a 5, so we can only use one of the fives.
1 x 1 x 2 x 3 x 5 = 30
the answer is 30
The Prime Factorization of 3,5,10 is:
3 = 1 x 3
5 = 1 x 5
10 = 2 x 5
Lets Multiply it:
We already have a 5, so we can only use one of the fives.
1 x 1 x 2 x 3 x 5 = 30 so 30 is the answer.
B)-5x + 5y - 5
C)5x + 5y + 5
D)-5x - 5y + 5
Answers
B: -5x + 5y - 5
Hope this is the answer you're looking for (:
2x - 8x - 6y + 9 - 14 + x + 11y
-6x + x - 6y + 11y - 5
-5x + 5y - 5
So the answer should be B
Answers
x-y=14
xy=1800
We can solve by substitution method.
x=14+y
(14+y)y=1800
14y+y²=1800
y²+14y-1800=0
Now, we solve this square equation:
y=[-14⁺₋√(196+7200)] / 2=(-14⁺₋86)/2
We have two solutions:
y₁=(-14-86)/2=-50 ⇒x=14+y=14-50=-36
y₂=(-14+86)/2=36 ⇒x=14+y=14+36=50
Answer: we have two solutions:
Solution1: The first number is -36 and the other number is -50
Soltuion2: The first number is 50 and the other number is 36
Answers
1 is the smallest possible integer.
Given that: .
The discreminant of this equation is:
For imaginary zeros, we must get discreminant less than 0.
So,
Next integer of 0.2 is 1.
So 1 is the smallest possible integer.
Learn more: brainly.com/question/20521181
The question is incomplete, the complete question is
Determine the smallest integer value of a for which f(x) = ax² - 2x + 5 has imaginary zeroes. Show how you found this answer
Answer:
The smallest integer value of a is 1
Step-by-step explanation:
To find the zeroes of a function equate it by 0, then find the values of x which are the zeroes of the function
To find the types of the roots (zeroes) of a function f(x) = ax² + bx + c use the discriminant of the function b² - 4ac
- If b² - 4ac > 0, then the function has two different real roots
- If b² - 4ac = 0, then the function has one real root
- If b² - 4ac < 0, then the function has no real roots (imaginary roots)
∵ f(x) = ax² - 2x = 5
- To find its zeroes equate f(x) by 0
∴ ax² - 2x + 5 = 0
∵ f(x) has imaginary zeroes
- That means the discriminant is less then zero
∴ b² - 4ac < 0
∵ a = a, b = -2 and c = 5
- Substitute them in the inequality above
∴ (-2)² - 4(a)(5) < 0
∴ 4 - 20 a < 0
- Add 20 a to both sides
∴ 4 < 20 a
- Divide both sides by 20
∴ 0.2 < a
- That means a is greater than 0.2
∴ a > 0.2
∵ You must to find the smallest integer value of a
- The first integer greater than 0.2 is 1
∴ a = 1
The smallest integer value of a is 1