Ms. Arango gave his daughter 50 chocolate bars to give to her friends at her birthday party. She gave 3 chocolates to each of her friends and still
had 2 chocolates left. Write an equation to determine the number of
friends (f) at Mr. Arango's daughter's party. *

Answers

Answer 1
Answer:

Answer:

Ans: 16

Step-by-step explanation:

50-2=48

48/3=16 friends

Answer 2
Answer:

Final answer:

To determine the number of friends at Mr. Arango's daughter's party, we can set up an equation. Each friend receives 3 chocolates, and 2 chocolates are left. By solving the equation 3f + 2 = 50, we find that there were 16 friends at the party.

Explanation:

To determine the number of friends (f) at Mr. Arango's daughter's party, we can set up an equation based on the information given. Let f represent the number of friends. Each friend receives 3 chocolates, so the total number of chocolates given out is 3f. We also know that 2 chocolates are left, so we can set up the equation:



3f + 2 = 50



To solve for f, we can subtract 2 from both sides:



3f = 48



Then, we divide both sides by 3 to isolate f:



f = 16



Therefore, there were 16 friends at Mr. Arango's daughter's party.

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Answers

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Answers

Answer:

Step-by-step explanation:

5-x< 13

-5      -5

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Answer:

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Step-by-step explanation:

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Answers

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Answers

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On a coordinate plane, a parabola opens up in quadrant 1. It goes through (2, 12), has a vertex at (5, 3), and goes through (8, 12). Write the equation of the function whose graph is shown. y = (x + )2 +.

Answers

Answer:

Step-by-step explanation:

You have a vertex coordinate and 2 points. In order to write the equation for that parabola, you only need the vertex and one point. We will fill in the following work form of the parabola:

y=a(x-h)^2+k , where h and k are from the vertex and x and y are from the point. Filling in:

12=a(8-5)^2+3 and

12=a(3)^2+3 and

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Answer:

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Step-by-step explanation:

Pwease help fast this is mah last question!The area of the trapezium ABCD as shown in the figure (in square units) is
A) 222
B) 111
C) 224
D) 116​

Answers

Answer:

A  = 222 units^2

Step-by-step explanation:

To find the area of this trapezoid, first draw an imaginary horizontal line parallel to AD and connecting C with AB  (Call this point E).  Below this line we have the triangle CEB with hypotenuse 13 units and vertical side (21 - 16) units, or 5 units.  Then the width of the entire figure shown can be obtainied using the Pythagorean Theorem:

(5 units)^2 + CE^2 = (13 units)^2, or 25 + CE^2 = 169. Solving this for CE, we get |CE| = 12.

The area of this trapezoid is

A = (average vertical length)(width), which here is:

       (21 + 16) units

A  = --------------------- * (12 units),   which simplifies to:

                  2

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