Answer:
35.34 atoms will be present after 14,325 years.
Step-by-step explanation:
Given : Carbon-14 has a half-life of approximately 5,730 years. This exponential decay can be modeled with the function N(t) = N0. If an organism had 200 atoms of carbon-14 at death.
To find : How many atoms will be present after 14,325 years?
Solution :
The half-life exponential function modeled is
Where, is the initial atoms
N is the total number of atoms.
t=14,325 years is the time
h=5,730 years is the half-life time
Substitute the value in the formula,
Therefore, 35.34 atoms will be present after 14,325 years.
Answer:
35.36 atoms
Step-by-step explanation:
Answer:
81%
Step-by-step explanation:
If there is a 30 percent chance a student will fail a class at Fresno State, we can simply multiply the percentage by the probabilities of all students failing. Every option available:
P(All four fail) = 1 student fails * 2 students fail * 3 students fail * 4 students fail
P(All four fail) = 0.3 * 0.3 * 0.3 * 0.3
P(All four fail) = 0.0081
0.0081 = 81%
Answer:
Gas used = 23/3-123/27
These are the choices:
x = 10; it takes 10 seconds to reach the maximum height and 10 seconds to fall back to the ground
x = 10; it takes 10 seconds to reach the maximum height and 20 seconds to fall back to the ground
x = 5; it takes 5 seconds to reach the maximum height and 10 seconds to fall back to the ground
x = 5; it takes 5 seconds to reach the maximum height and 5 seconds to fall back to the ground
-4(s)²+t³÷5