[3b+9]-16=-52
i just want to see if i got the correct answer my answer was
b=-15

Answers

Answer 1
Answer:

Yes, the answer to the given maths solution is indeed is b = -15

How to solve this mathematical problem

3(-15) = -45

-45 + 9 = -36

-36 - 16 = -52

so b = -15

Hence, your initial answer is correct.

Read more about algebra here:

brainly.com/question/4344214

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Answer 2
Answer:

Answer:

yes, the answer is b = -15

Step-by-step explanation:

3(-15) = -45

-45 + 9 = -36

-36 - 16 = -52

so b = -15


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The product of d and 4

Answers

Answer: 4d

Step-by-step explanation:

Product means multiplication, so the product of d and 4 means d times 4.

Ralph spends 15 1/3 hours per month playing tennis. How many hours does he play in a year?A.)164 1/3
B.)182 2/3
C.)164
D.)184

Answers

1\ month\ \rightarrow\ \ 15 (1)/(3) \ hours\n12\ months \ \rightarrow\ x\n\nx=12\cdot 15 (1)/(3)\n\nx=12\cdot15+12\cdot (1)/(3) \ \ \ \Rightarrow\ \ \ x=180+4=184\ [hours]\n\nAns.\ In\ the\ year\ he\ play\ 184\ hours\ \ \ \Rightarrow\ \ \ D.
Multiple hours per month by the months per year.

In this case, 15.33333 by 12 = 184

If f(x) = x2 + 2x + 3, what is the average rate of change of f(x) over the interval [-4, 6]? A. 51

B. 40

C. 31

D. 20

E. 4

Answers

Calculating the value of f(x) for the given interval.

For x = - 4, f(x) = f(- 4) = (- 4)^2 + 2 (- 4) + 3 = 11

For x = 6, f(x) = f(6) = (6)^2 + 2 (6) + 3 = 51

Now using formula for the calculation of average rate of change of f(x) over the given interval of [- 4, 6];

(f(b) – f(a)) / b – a = (f(6) – f(- 4)) / 6 – (- 4) = (51 -11) / 10 = 4

So option “E” is correct.

Order these from least to greatest

Answers

order what there is nothing to order sorry

2.3 + 6.82 ÷ 3.74 + 1.09

Answers

2.3  + 6.82 : 3.74 + 1.09 = 3.39 + 1.8 = 5.19 
BIDMAS
6.82/3.74 = 1.82352941176
2.3 + 1.09 = 3.39
1.82352941176 + 3.39 = 5.21352941176

Unless you didn't include brackets, which would result in a different answer

Ax+by=1
bx-ay=a+b
solve in linear equation in 2 variables

Answers

\left\{\begin{array}{ccc}ax+by=1&/\cdot a\nbx-ay=a+b&/\cdot b\end{array}\right\n\n+\left\{\begin{array}{ccc}a^2x+aby=a\nb^2x-aby=ab+b^2\end{array}\right\n------------\n.\ \ \ \ \ a^2x+b^2x=a+ab+b^2\n.\ \ \ \ \ \ (a^2+b^2)x=a+ab+b^2\n.\ \ \ \ \ \ \ \ \ \ \ \ x=(a+ab+b^2)/(a^2+b^2)\n\na\cdot(a+ab+b^2)/(a^2+b^2)+by=1\n\n(a^2+a^2b+ab^2)/(a^2+b^2)+by=1\n\nby=1-(a^2+a^2b+ab^2)/(a^2+b^2)

by=(a^2+b^2)/(a^2+b^2)-(a^2+a^2b+ab^2)/(a^2+b^2)\n\nby=(a^2+b^2-a^2-a^2b-ab^2)/(a^2+b^2)\n\nby=(b^2-a^2b-ab^2)/(a^2+b^2)\n\ny=(b^2-a^2b-ab^2)/(a^2b+b^3)

y=(b(b-a^2-ab))/(b(a^2+b^2))\n\ny=(b-a^2-ab)/(a^2+b^2)\n\nAnswer:\n\nx=(a+ab+b^2)/(a^2+b^2)\ and\ y=(b-a^2-ab)/(a^2+b^2)
ax+by=1
bx-ay=a+b
The solution in attached file