Answer: -630
Step-by-step explanation:
Given the nth term of a sequence;
a(n)=a(n−1)⋅(−9) and the first term of the sequence a(1) as 35, the third term of the sequence can be gotten by using the formula at when n = 3
If n = 3 and a(1) = 35;
a(3) = 35(3-1)•(-9)
a(3) = 35×2×-9
a(3) = 70×-9
a(3) = -630
There the 3rd term of the series will give us -630 according to the nth term of the formula given.
The problem is about a recursive sequence where each term is the previous term multiplied by -9. After applying this rule twice, it is found that the 3rd term of the sequence is 243.
The problem provided indicates a recursive sequence, where each term is based on the previous term. The sequence is defined as a(1) = 3 and a(n) = a(n - 1) ⋅ (−9), which essentially means that each subsequent term is the previous term multiplied by -9.
To find the 3rd term, we apply this rule twice starting from the first term:
a(2) = a(1) * (-9) = 3 * (-9) = -27
a(3) = a(2) * (-9) = -27 * (-9) = 243
Therefore, the 3rd term of the sequence is 243.
#SPJ3
b. –2x + 5y = –6 4x – 2y = 4
c. 5x – 2y = –6 3x – 4y = 2
d. 2x + 3y = 10 4x + 5y = 18
In my opinion and as what I learned last year the correct answer is HL.