Answer:
$37.8125
Step-by-step explanation:
$2.75 x 12.5 = 34.375
34.375 x 10% = 3.4375
$34.375 + 3.4375 = 37.8125
Answer: 3/4 + 7/12 - (-4) = 3/4 + 7/12 + 4 (two minuses make a plus)
3/4 + 7/12 + 4/1 = 9/12 + 7/12 + 48/12 (4 = 4/1 or 4 divided by 1)
(to add the fractions the denominators need to be the same. Multiply both the denominator and numerator by the same number)
(9+7+48)/12 = 64/12 = 5 and 1/3 or 16/3
We can also get this answer by leaving the 4 as a whole number:
9/12 + 7/12 +4 = 16/12 + 4 = 1 and 1/3 + 4 = 5 and 1/3
If you put the sum in a calclator you also get 5 and 1/3.
Hope this helps :)
(5x2 + 2x + 11) − (7 + 4x − 2x2)
Answer:
7x² - 2x + 4
Step-by-step explanation:
(5x² + 2x + 11) - (7 + 4x - 2x²) = 5x² + 2x + 11 - 7 - 4x + 2x² =
(5x² + 2x²) + (2x - 4x) + (11 - 7) = 7x² - 2x + 4
Answer:
completing the square.
Step-by-step explanation:
trust me
Answer:20 cm
Step-by-step explanation:
Volume of cone=540π
Radius=r=9
Volume of cone=1/3 x π x r^2 x h
540π=1/3 x π x 9^2 x h
540π=1/3 x π x 9 x 9 x h
540π=(1xπx9x9xh)/3
540π=(81πh)/3
540π=27πh
Divide both sides by 27π
540π/27π=(27πh)/27π
20=h
h=20
Height =20 cm
Call the point of intersection of the diagonals point X.
Each base is the hypotenuse of an isosceles right triangle whose sides are the diagonals and whose 90° angle is at X. The altitude of that triangle (⊥ distance to the base from X) is half the length of the hypotenuse. Then the height of the trapezoid is half the sum of the base lengths.
The area of the trapezoid is the product of the height and half the sum of the base lengths, hence is the square of half the sum of the base lengths.
... Area = ((16 cm +30 cm)/2)² = (23 cm)² = 529 cm²
The area of the given isosceles trapezoid is 345 square cm.
To solve this problem, we need to remember that the area (A) of a trapezoid is given by the formula A = 0.5 * (b1+b2) * h, where b1 and b2 are the lengths of the two bases and h is the height. When the diagonals of an isosceles trapezoid are perpendicular to each other, it can be divided into two right triangles with bases 7 cm and 16 cm (as 30-16=14 and 14/2=7) and height h. From here, we can calculate that the hypotenuse (diagonal) is equal to sqrt(7^2 + 16^2) = 17. Hence, it is a Pythagorean triple, meaning the height is 15 cm. Using the formula for the area of a trapezoid, we can now calculate the area to be 0.5 * (16+30) * 15 = 345 cm^2.
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ASA we need a second angle that is next to the side
SAS we need a side next to the angle
Choice B