Consumer math help!!!??????? Pic attached

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Answer 1

Answer: 1:decreases, 2:792.50, 3: 707.50

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4/9 of the 270 members of a hunting club are females. How many male members are there ?

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In a right triangle, if the length of the hypotenuse is 39 and the length of one of the other sides is 15, what is the length of the third side?

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Answer:

either way the answer is be =36 so the length of the missing side is 36 CM.

One student makes 20 origami figures that they want to give to 9 friends. Which of the following best describes how the origami can be most evenly divided between the friends.

Answers

Answer:

give each friend 2 origami figures

Step-by-step explanation:

Lyra and Donna are testing the two-way radios they built for their high school science project. Lyra goes to the top of a building that is 22 meters high with one of the radios and stands directly above the building’s entrance. Donna walks out of the entrance, perpendicular to the building, with the other radio. If Donna is more than 50 meters from the entrance, the connection between the radios breaks. What is the range of communication for the two radios to the nearest meter?

Answers

We use the Pythagorean Theorem: c^2=a^2+b^2. In this case :
c-nearest range between two radios
a=22 m ( height of a building)
b=50 m ( distance from an entrance)
c^2=22^2+50^2˝=484+2500=2984
Finally: c=sqrt(2984) (square root of 2984)=54.626 m
Answer: The range of communication for the two radios is 54.626 meters.

D= 11/5(p-15)

solve for p.

Answers

Answer: The required solution for p is $p=(11+75D)/(5D).$

Step-by-step explanation: We are given to solve the following equation for the unknown variable p :

$D=(11)/(5(p-15))~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To solve the given equation for p, we must find the value of p in terms of D.

From equation (i), we have

$D=(11)/(5(p-15))\n\n\n\Rightarrow D=(11)/(5p-75)\n\n\n\Rightarrow D(5p-75)=11\n\n\Rightarrow 5Dp-75D=11\n\n\Rightarrow 5Dp=11+75D\n\n\Rightarrow p=(11+75D)/(5D).$

Thus, the required solution for p is $p=(11+75D)/(5D).$

D=11/5p-33
11/5p=D+33
p=5/11D+15

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