Of a group of 500 people, 60 are fit enough to climb Mount Shasta in California. The group has 300 women and 200 men. 12% of the men are fit to climb the mountain. What is the probability that a person picked at random from the group is a male or is fit to climb Mount Shasta? A) 59/125 B) 49/100 C) 13/25 D) 56/125

Answers

Answer 1
Answer:

NO, that answer is wrong it is not13/25

Answer: 0.472 (or in percent near 47.2%).

if you simplify 0.472 and turn it into a fraction you will get  59/125


that is the answer on plato

Answer 2
Answer: P(men) or P(fit) = P(men) + P(fit) = 200/500 + 60/500 = 260/500 = 13/25

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At the amusement park, the ratio of children to adults is 5:2. If 63000 people visit the park, how many are children?

Answers

If you think about it, the ratio of 5:2, is basically saying that for every 7 people you have, 5 will be children, and 2 will be adults, or 5/7 : 2/7. So you can set it up as a proportion. If you are looking for the number of children (5 for every 7), you could as 5/7 = x/63000. If you did cross-multiplication (5*63000 = 7*x), you would get that 7x = 315000. If you them divide both sides by 7 to get the variable by itself, you would get that x is equal to 45000. This means that out of the 63000 people in the park, 45000 of them are kids.

Subtract 2F2Csixteen -92sixteen =

Answers

Choice-'B' is the correct choice . . . 2E9A .

I began converting the original numbers to decimal (base 10),
but decided that 5 points are not worth that much aggravation.

At that point, I wondered whether I could just write it down and
do it like any old other subtraction exercise.  I've never done
that before with hex numbers, but I found that I could ! 

The only place you have to be extra careful is in the third place,
where you have to subtract '9' from '2'.  In order to do that, you
have to borrow one from the 'F'.  That makes the 'F' an 'E', and
it makes the '2' an '18', from which you can then easily subtract
the '9'.  The difference of '2E9A' then jumps right out.

Thank you.  I never knew you could just do that.
2F2C-92=2E9A

What are the factor pairs of 23?

Answers

it is a prime, it doesn't have, the only (I don't know if your system counts 1,23 as factors but there are no others)

Cx/2=ag answer needed for x

Answers

Cx/2=ag 
First multiply each side by 2            Cx=2ag
Then divide by C on both sides       x=2ag/C

ANSWER: x=2ag/C
The answer to this answer is 56 

21x^3 + 6x^2 - 28x - 8 factor this expression with work please?

Answers

21x^3 + 6x^2 - 28x - 8 \n \n 3x^2 (7x + 2) - 4(7x + 2) \n \n (7x + 2)(3x^2 - 4) \n \n

The final result is: (7x + 2)(3x² - 4).
21x^3+6x^2-28x-8
(21x^3+6x^2)-(28X+8)
3x^2(7x+2)-4(7x+2)
3x^2-4=0 and 7x+2=0

Help! Simplify (see photo) pls explain
If you don’t know pls don’t answer thanks

Answers

Answer:

-8 √(6)

Step-by-step explanation:

4i√(-24) \n4i√(-1) *√(24) \n4i*i*√(4)*√(6)\n-4 * 2*√(6) \n-8 √(6)

.

√(-1) =i \ni*i = -1