The fluoride ion (F-) is smaller in size than the oxide ion (O2-).
The ion with a smaller size is F- (fluoride ion) compared to O2- (oxide ion).
The size of an ion depends on the number of protons and electrons it has. Fluoride ion has one less electron than the oxide ion, making it smaller in size.
This trend can be explained by the concept of effective nuclear charge, where the positive charge of the nucleus is partially shielded by other electrons in the atom. As the atomic number increases from oxygen to fluorine, the increase in nuclear charge outweighs the additional electron-electron repulsions, resulting in a smaller size for fluoride ion.
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Answer:
Non metal.
Explanation:
The periodic table is arrangements of the elements into a particular order based on their atomic number .
In general when we move from left to right in a periodic table the metallic properties of the elements decreases. So we can say that the left most elements are metals and the right most elements are non metals.
Now as carbon is placed on the right side of the periodic table as it is considered to be non metal.
The reaction is begun with 161.00 g of Si and 139.00 g of Cr2O3.
How many grams of the excess reactant is left after the reaction is complete?
Answer: 122.9 g of will be left from the given masses of both reactants.
Explanation:
To calculate the moles :
According to stoichiometry :
2 moles of require 3 moles of
Thus 0.91 moles of will require= of
Thus is the limiting reagent as it limits the formation of product and is the excess reagent.
Thus (5.75-1.36) = 4.39 moles of excess reagent.
Mass of
Thus 122.9 g of will be left from the given masses of both reactants.
1s22s23s22p1
1s32s32p1
1s12s12p5
Answer : The correct option is,
Explanation :
Electronic configuration : It is defined as the arrangement of the electrons of an atom in an atomic orbital.
The given element is, nitrogen.
The nitrogen element belongs to group 15 and the atomic number of nitrogen is 7.
As we know that the number of electrons is equal to the number of atomic number.
The number of electrons present in nitrogen = 7
Thus, the electronic configuration of nitrogen is,
1s22s22p3 considering N is the third element in the 2nd P sublevel
Answer:
Se + 2e- => Se-2
Explanation:
Ions are electrically charged particles, formed due to the gain or loss of electrons by an atom.
There are two types of ions cations and anions. An element that loses their electrons and forms positive ions are cations while metals and element that gains one or more electrons and forms negative ions are anions.
Selenium is an atom with atomic number 34 and represented as Se. The electronic configuration of Se is 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p4. Selenium will gain 2 more electrons to complete it p orbital and form an ion Se-2.
The equation is as below:
Se + 2e- => Se-2