At a zoo, the lion pen has a ring-shaped sidewalk around it. The outer edge of the sidewalk is a circle with a radius of 11 m. The inner edge of the sidewalk is a circle with a radius of 9 m. Find the exact area of the larger circle
Find the exact area of the smaller circle.
Write an expression to find the exact area of the sidewalk (shaded portion).
Find the approximate area of the sidewalk. Use 3.14 to approximate π.
Answer:
Find the exact area of the larger circle. Show your work. (1 point)
A= N x 11 2 A = n?

Find the exact area of the smaller circle. Show your work. (1 point)
A= n 9 2 A=n?

Write an expression to find the exact area of the sidewalk (shaded portion). Show your work. (2 points) 11 2 – 9 2 x n

Find the approximate area of the sidewalk. Use 3.14 to approximate π. Show your work. (1 point) 11 2 x 3.14 – 9 2 x 3.14=

Answers

Answer 1

Answer: Well first lets find area of the entire circle itself

We have the radius be 11.

Pie x radius^2 = A

11 squared is 121.

So we have:

Pie x 121 = area

Pie is 3.14.

The area of the entire circle is exactly 379.94 m.

Now lets put this off to side and solve the inner circle.

Same thing:

Radius of the inner circle is 9.

Pie x radius^2 = Area

9 squared is 81.

So now:
Pie x 81 = area

Pie is 3.14

3.14 x 81 = exactly 254.34.

The inner pen is exactly 254.34 m

So now knowing :

The whole circle is 379.94
And the inner circle is 254.34

We can subtract the inner circles area from the whole circle and get the area of the outer circle/sidewalk.

379.94 - 254.34 = 125.6

The outer circle/sidewalk is 125.6 m

With this info we can answer your questions.

The exact area of the larger circle is 379.94 m

The exact area of the inner circle is 254.34 m

Expression:
If
Large circle = L
Small circle = S
Sidewalk = W

An expression would be L - S = W

The sidewalk area is exactly 125.6 m

To show your work read what i did above and just show how i did Pie x radius = area.

Hope this helps!
Brainliest is always appreciated if you feel its deserved.

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V = u + 10t
Work out the value of v when
u = 10 and t = 7

Answers

well, we have to plug in the values and then solve for v

v=10 + 10 times 7

by order or operations 10 times 7=70 plus 10 is 80

so v=80

if u=10 and t=7

first: plug in the numbers (V=10+10(7))

second: use PEMDAS to solve

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V=80

I am a 2 dimensional shape. my perimeter is also known as a circumference

Answers

a circle...... maybe???

The answer is circle. The only two dimensional shape that uses circumference as a perimeter is a circle.

A commercial aircraft gets the best fuel efficiency if it operates at a minimum altitude of 29,000 feet and a maximum altitude of 41,000 feet. Model the most fuel-efficient altitudes using a compound inequality.

Answers

Answer:

$x\geq 29,000$ and $x\leq 41,000$

Step-by-step explanation:

Let x be the altitude of a commercial aircraft

=>The expression " A minimum altitude of 29,000 feet" is equal to

$x\geq 29,000$

All real numbers greater than or equal to 29,000 ft

=>The expression " A maximum altitude of 41,000 feet" is equal to $x\leq 41,000$

All real numbers less than or equal to 41,000 ft

therefore, The compound inequality is equal to

$x\geq 29,000$ and $x\leq 41,000$

All real numbers greater than or equal to 29,000 ft and less than or equal to 41,000 ft

The solution is the interval [29,000,41,000]

A line has slope 2/3 and y-intercept -2. Which answer is the equation of the line?A) y=2x+2/3
B) y= -2x+2/3
C) y=2/3x+2
D) y=2/3x -2

Answers

b. is the correct answer

What is the value of x in the equation 3(2x + 4) = −6?a) −3
b)1
c)12
d)19

Answers

A. 2x-3= -6+4= -2x3= -6

Your answer is A. -3

What is the determinant of the coefficient matrix of this system?
4x-3y=-8
8x-3y=12

Answers

The coefficient matrix is build with its rows representing each equation, and its columns representing each variable.

So, you may write the matrix as

$\left[\begin{array}{cc}\text{x-coefficient, 1st equation}&\text{y-coefficient, 1st equation}\n\text{x-coefficient, 2nd equation}&\text{y-coefficient, 2nd equation} \end{array}\right]$

which means

$\left[\begin{array}{cc}4&-3\n8&-3\end{array}\right]$

The determinant is computed subtracting diagonals:

$\left | \left[ \begin{array}{cc}a&b\nc&d\end{array}\right]\right | = ad-bc$

So, we have

$\left | \left[\begin{array}{cc}4&-3\n8&-3\end{array}\right] \right | = 4(-3) - 8(-3) = -4(-3) = 12$

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