Answer: To help eliminate subjectivity
Explanation:
Edgenuity 2020
Answer:
0.25 m
Explanation:
The intensity of the magnetic field around a current-carrying wire is given by:
where
where
is the permeabilty of free space
I is the current
r is the distance from the wire
In this problem, we know:
is the magnetic field
is the current in the wire
Re-arranging the equation, we can find the distance of the field from the wire:
Explanation:
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A = side length (L/2) ; distance between plates (d) ; dielectric current (k)
B = side length (L) ; distance between plates (d/2) ; dielectric current (4k)
C = side length (2L) ; distance between plates (d) ; dielectric current (2k)
D = side length (L) ; distance between plates (2d) ; dielectric current (2k)
The capacitance of the four capacitors, ranked from highest to lowest, is B = C (they both have equal capacitance), followed by D, and then A.
The capacitance of a parallel-plate capacitor is given by C = εA/d, where ε is the permittivity of the dielectric material (which is equal to the product of the vacuum permittivity and the relative permittivity or dielectric constant k), A is the area of one of the plates, and d is the separation between the plates.
Applying this formula to the four capacitors and simplifying:
When ranked from highest to lowest capacitance, the order will be B = C > D > A.
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