Answer:
a) 8*10^-8C/m²
b) +9.04*10^3N/C
c) = -9.04*10^3N/C
Explanation:
Given
Side length, L = 50cm = 0.5m
Charge on the plate, Q = 4*10^-8C
Surface charge density, σ = Q/A
The surface charge density of each part is then half of the total charge density of the plate. Thus,
σ(face) = 1/2σ
σ(face) = Q/2A
σ(face) = Q/2L²
Now we plug in, since we have Q and L
σ(face) = 4*10^-8 / 2*0.5²
σ(face) = 4*10^-8 / 0.5
σ(face) = 8*10^-8C/m²
Magnitude of electric field above the plate is,
E = σ(face) / E•
E = 8*10^-8 / 8.85*10^-12
E = 9.04*10^3 N/C
If we assume this plate lies on the side of the "xy" plane, the electric field is directed in the positive "z" direction. As such,
E = +9.04*10^3N/C
Electric field below the plate has the same magnitude, but different direction. So, E = -9.04*10^3N/C
Answer:
A series circuit
Explanation:
b. the height of high tides varies with the phases of the moon.
c. spring tides and neap tides affect the phases of the moon.
d. the moon revolves around the Earth every 14 days.
Please select the best answer from the choices provided
Answer:
D
Explanation:
Because neap and spring tides happen twice a month during new moon and full moon .It occurs twice in a month which is 14 days
Answer:
i think it is d
Explanation:
Answer:
If the frequency of the source is increased the current in the circuit will decrease.
Explanation:
The current through the circuit is given as;
Where;
V is the voltage in the AC circuit
Z is the impedance
Where;
R is the resistance
is the inductive reactance
= ωL = 2πfL
where;
L is the inductance
f is the frequency of the source
Finally, the current in the circuit is given as;
From the equation above, an increase in frequency (f) will cause a decrease in current (I).
Therefore, If the frequency of the source is increased the current in the circuit will decrease.
Part A
Which mineral will dissolve easily in water?