4. solve
e) 4^x-10.2^x+16=0
I think the dot means multiply?

Answers

Answer 1
Answer: 4^x-10\cdot2^x+16=0\Rightarrow(2^2)^x-10\cdot2^x+16=0\Rightarrow(2^x)^2-10\cdot2^x+16=0

subtitute\ 2^x=t > 0\n\nt^2-10t+16=0\nt^2-2t-8t+16=0\nt(t-2)-8(t-2)=0\n(t-2)(t-8)=0\iff t-2=0\ or\ t-8=0\n\nt=2\ or\ t=8\n\nt=2^1\ or\ t=2^3\n\ntherefore\ 2^x=2^1\ or\ 2^x=2^3\n\nAnswer:\boxed{x=1\ or\ x=3}
Answer 2
Answer: 2^x=a
4^x=(2^2)^x=(2^x)^2=a^2

a^2-10a+16=0
Δ=10^2-4*1*16=100-64=36
√Δ=6
a1=(10+6)/2=16/2=8
a2=(10-6)/2=4/2=2
2^x=8=2^3⇒ x=3 or
2^x=2=2^1⇒ x=1


There are 2 solutions : x=1 or x=3

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Hello, 

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