Answer:
675= 3.14× r²
r²= 675/ 3.14
r²=214.968
radius=14.66 meters
diameter= 2× radius
diameter= 2× 14.66
diameter = 29.32 meters
The values of a, b, and c needed to write given quadratic equation in its general form: a = 1/4 , b = 0 and c = 5
"It is a mathematical statement which consists of equal symbol between two mathematical statements."
"A polynomial equation of degree 2 is a quadratic equation."
For given question,
We have been given a quadratic equation 1/4x² + 5 = 0
We know that the general for of quadratic equation is ax² + bx + c = 0
where a, b, c are real numbers with a ≠ 0.
We need to write given quadratic equation in the standard form and find the corresponding value for a, b, and c.
Comparing given quadratic equation with the general form of quadratic equation we have,
a = 1/4 , b = 0 and c = 5
Therefore, the values of a, b, and c needed to write given quadratic equation in its general form: a = 1/4 , b = 0 and c = 5
Learn more about the equation here:
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Answer:
6 cm
Step-by-step explanation:
I don't know may I use the trigonometry functions, therefor I'm going to use Pythagorean theorem and property of 30°-60°-90° triangle.
m∠ACB = 120° ⇒ m∠ACD = 60° ⇒ m∠DAC = 30°
DC is opposite to 30° angle ⇒ AC = CB = 8 cm
From ΔADC: AD² = 64 - 16 = 48 ; AD = 4√3 cm
ΔACB is isosceles ⇒ m∠CAB = m∠CBA = 30°
m∠DAH = m∠DAC + m∠CBA = 2(30°) = 60° ⇒ m∠ADH = 30° ⇒ AH = 4√3 ÷ 2 = 2√3 cm
From ΔADH: DH = = √36 = 6 cm
b. 0.64
c. 0.62
d. 0.75
e. 0.48
Answer:
(2x - 3a³) ,(2x + 3a³)
Step-by-step explanation:
Given that
4x^2-9a^6
As we know that
x² - y² = ( x+y)(x-y)
So
4x^2-9a^6 = (2x)² - (3a³)²
By using the above formula
x² - y² = ( x+y)(x-y)
4x^2-9a^6 = (2x)² - (3a³)²
4x^2-9a^6 = (2x - 3a³) (2x + 3a³)
So the factor is (2x - 3a³) ,(2x + 3a³)
To verify
Multiple both factors
(2x - 3a³) (2x + 3a³) = 2x .2x -2x . 3a³ + 3a³ . 2x - 3a³. 3a³
=4x² - 9 a ⁶