A furniture company makes large and small chairs. A small chair takes 30 minutes of machine time and 75 minutes of labor to build. A large chair takes 40 minutes of machine time and 80 minutes of labor to build. The company has 57 hours of labor time and 26 hours of machine time available each day. How many of each type of chair is built in a day?

Answers

Answer 1

Answer: Let the number of large chairs be x and small chairs be y
40x + 30y = 26 x 60 = 1,560 . . . . (1)
80x + 75y = 57 x 60 = 3,420 . . . . (2)

(1) x 2 => 80x + 60y = 3,120 . . . . (3)

(2) - (3) => 15y = 300 => y = 300/15 = 20

From (2), 80x + 75(20) = 3,420 => 80x + 1,500 = 3,420 => 80x = 3,420 - 1,500 = 1,920 => x = 1,920/80 = 24

Therefore, the company should produce 24 large chairs and 20 small chairs.

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Each hour, the number of bacteria in Dr. Nall’s petri dish tripled. What percent is the population compared to the population the hour before?A. 3%
B. 30%
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D. 300%

Answers

Answer:

Option D. 300%

Step-by-step explanation:

Let the number of bacteria in Dr Nall's petri dish = x

After one hour number of bacteria in the petri dish = 3x

So the percentage of the population compared to the population the hour before will be

= $\frac{\text{Population after 1 hour}}{\text{Population before 1 hour}}* 100$

= $(3x)/(x)* 100$

= 300%

Therefore, Option D. will be the answer.

THE ANSWER IS THE D!!!!!!!!!!!!

Sonji paid $25.00 for two scarves, which were different prices. When she got home she could not find the receipt. She remembered that one scarf cost $3 more than the other. What was the price of the more expensive scarf?

Answers

25÷2=$12.50 12.50+3=$15.50 n the other $9.50

Answer:

The answer is C

Step-by-step explanation:

In a day, Robin spends 6 hours at school, sleeps for 9 hours, plays for 3 hours, and spends the rest of the time doing other things. Robin spends ______% of the day playing and _____% of the day doing things other than sleeping, playing, or going to school.

Answers

Answer:

Robin spends 12.5% of the day playing and 25% of the day doing things other than sleeping, playing, or going to school.

Step-by-step explanation:

In a day, Robin spends his time :

At school = 6 hours

Sleeps = 9 hours

Plays = 3 hours

Total time spent = 6 + 9 + 3 = 18 hours

Time left = 24 - 18 = 6 hours

doing other things = 6 hours

Now we have to calculate what % of the day he is playing and doing other things.

He spends 3 hours in playing = 3 hours of 24 hours

= 3 ÷ 24 × 100 = 12.5%

He spends 6 hours in doing other things = 6 hours of 24 hours

= 6 ÷ 24 × 100 = 25%

Robin spends 12.5% of the day playing and 25% of the day doing things other than sleeping, playing, or going to school.

6hrs = school
9hrs = sleeps = 18hrs // 24hrs ----6hrs left
3hrs = plays

6hrs = other things

playing = 12.5% -- 3/24 3/24*100
other things = 25% -- 6/24 6/24*100

Simplify and write your answer without exponents 16^(-5/4)

Answers

$16^{ -(5)/(4)} \n \n 2^(-5) \ / \ simplify \n \n (1)/(2^5) \ / \ negative \ power \ rule \n \n (1)/(32) \ / \ simplify \n \n Answer: \fbox {1/32} \ or \fbox {0.0313}$

-2(x + 2) > 3

“With a step-by-step explanation be specific”

Answers

Answer:

x < - 7/2 (it's 7 over 2 not 7 divided by 2)

Step-by-step explanation:

The picture is the graph

Solve: ∫e^u/(1−eu)^2du

Answers

Answer:

Hi,

Step-by-step explanation:

$Let's\ say\ v=1-e^u \n\n\displaystyle \int\limits {\frac{e^u } { (1-e^u)^2 }} \, du \n\n\n=\int\limits {(1)/(v^2) } \, dv \ \n\n=-(1)/(u) +C\n\n=-\frac{1 } { 1-e^u } + C$

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