Another rock in Death Valley at the Racetrack traveled 55.3 meters during the observation period of nine years. a . What was the rock's average speed in feet per year? Round your answer to the nearest whole number. feet per year b . If a strong wind gives a stone an initial velocity of v 0 = 11 m / s , and the friction coefficient of stone on ice is μ = 0.14 , and g = 9.81 m / s 2 . Use the equation v 2 0 = 2 μ g S to find the stopping distance S for the stone. Round your answer to the nearest tenth.

Answers

Answer 1
Answer:

Answer:

a) 20 feet per year

b) 44.1 m

Step-by-step explanation:

Given:

Distance traveled during the observation period = 55.3 meters

Observation period = 9 years

initial velocity of v₀ = 11 m/s

friction coefficient of stone on ice is μ = 0.14

g = 9.81 m/s²

also,

v₀² = 2μgS

Now,

1 m = 3.28084 ft

thus,

Total distance in feet = 55.3 × 3.28084 = 181.430452 ft

Average speed = \frac{\textup{Distance}}{\textup{Time}}

or

Average speed = \frac{\textup{181.430452}}{\textup{9}}

or

Average speed = 20.159 feet/year ≈ 20 feet per year

b) v₀² = 2μgS

substituting the values in the above equation, we get

11² = 2 × 0.14 × 9.81 × s

or

121 = 2.7468 × s

or

s = 44.051 ≈ 44.1 m


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Answer:

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Simplify the quotient show the work 5 divided by nine

Answers

1.8 that is the best answer

Answer:

0.56

Step-by-step explanation:

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Answers

Answer:

7x+7y

Step-by-step explanation:

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Solve the system of equations.

6x - 5y = 15

X= y + 3

Answers

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Suppose you have a random variable that is uniformly distributed between 80 and 667. What is the probability of observing a random draw greater than or equal to 314? Answer to three decimal place if necessary.

Answers

Answer:

P(x>=314) = 354/588 = 0.602

Step-by-step explanation:

At first, we will find the sample space S

S = 667-80+1.  i.e 80 and 667 are included

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The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − x − π 2 + 1 6 x − π 2 3 + R3(x). Using this, estimate cos(88°) correct to five decimal places.

Answers

Final answer:

Cos(88°) can be estimated using the 3rd degree Taylor polynomial for cos(x) centered at a = π/2. The degrees need to be converted to radians, and by substituting into the polynomial, the cosine value to five decimal places is approximately 0.03490.

Explanation:

To estimate cos(88°) using the 3rd degree Taylor polynomial for cos(x) centered at a = π/2, we first need to convert 88 degrees to radians as cos(x) expects x in radians. 88 degrees is roughly 1.53589 radians. Now, substituting x = 1.53589 into the Taylor polynomial yields the estimate.

The given Taylor polynomial is represented as cos(x) = - (x - π/2) + 1/6 * (x - π/2)³. Substituting x with 1.53589, we get:

cos(1.53589) = - (1.53589 - π/2) + 1/6 * (1.53589 - π/2)³

To get the estimate correct to five decimal places, you calculate the above expression to get roughly 0.03490. Therefore, cos(88°) is approximately 0.03490.

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Final answer:

First, we convert the given angle 88° into radians, since standard trigonometrical functions take angles in radians. We then substitute this into the Taylor series given, keeping in mind the importance of the remainder term.

Explanation:

This problem deals with the concept of Taylor series approximation, which is a widely used method in mathematics to estimate the value of functions. The given Taylor polynomial approximates the cosine function. To estimate cos(88°), we first need to convert the angle from degrees to radians, because the standard trigonometric functions in mathematics take input in radians. Remember that 180° equals π radians. So 88° can be represented as (88/180)π radians.

Substitute this into the provided series − x − π/2 + 1/6 * (x − π/2)³ + R3(x). Be wary of the remainder term R3(x). This term ensures the correctness of the approximation on the interval of convergence. The closer x is to the center, the more accurate the approximation. In practical computations, you might need to take more terms into account to ensure sufficient accuracy to five decimal places in this case.

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