Solve for z in terms of v, w, x, and y.
vy = -ZWx
Z =
I

Answers

Answer 1
Answer:

Answer:

lots of letters

Step-by-step explanation:


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Suppose that we have a right triangle $ABC$ with the right angle at $B$ such that $AC = \sqrt{61}$ and $AB = 5.$ A circle is drawn with its center on $AB$ such that the circle is tangent to $AC$ and $BC.$ If $P$ is the point where the circle and side $AC$ meet, then what is $CP$?
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Choosing a 4-letter password using only 5 letters that may each be used more than once.

Answers

Wait a password with 4 letters using only 5? And the letters can be used more than once. I’m confused
How’s that even a question?

The ice skating rink charges an hourly fee for skating and $3 to rent skates for the day. Gillian rented skates and skated for 3 hours and was charged $21. Which equation represents the cost, c(x), of ice skating as a function of x, the number of hours of skating?

Answers

Answer:

The equation represents the cost, c(x), of ice skating as a function of x is c(x)=6x+3.

Step-by-step explanation:

Consider the provided information.

Let R be the per hour rate of the using the skating rink.

It is provided that $3 is the rent of skates for the day.

If Gillian rented skated and paid $21 after 3 hours of skating, this can be represented as:

21=3R+3

3R=18

R=(18)/(3)=6

Therefore, the hourly fee for skating is $6.

Now, write the equation represents the cost c(x) of the ice skating as a function of x.

Total cost = Number of hours × Hourly fee + Rent skates for the day.

Replace total cost with c(x), Number of hours with x, Hourly fee with 6 and rent skates of the day with 3.

Thus the required equation is:

c(x)=6x+3

Thus, the equation represents the cost, c(x), of ice skating as a function of x is c(x)=6x+3.

c(x) = 6x + 3

$6 per hr..and $3 for the skates

check..
c(x) = 6x + 3
he skated for 3 hrs and was charged $21
c(3) = 6(3) + 3
c(3) = 18 + 3
c(3) = 21
.so it is c(x) = 6x + 3

A teacher is covering a bulletin board with fabric. He has a piece of material that is 2 yards long and 36 inches wide. What size bulletin board can he cover with the material?

Answers

36'' = 1 yard
The teacher can cover a bulletin board with size 2 yards^2
Well to start our problem we need to find the information that is most important. 2 yards and 36 inches wide, and "What size bulletin board can he cover with the material?". Now that we have our information we can figure this out : 36 : 1y yard so 2y by 36in aka 2/36, so......our work can lead us too : 2 yards *squared* or 2 yards^2. Hopes I helped!

How do I solve for n?

Answers

4n-2=p\ \ \ \ |add\ 2\ to\ both\ sides\n\n4n=p+2\ \ \ \ |divide\ both\ sides\ by\ 4\n\n\boxed{n=(p+2)/(4)}

Given
y=x²+4x+3
find the vertex,
focus and
directrix

Answers

Answer:

Step-by-step explanation:

The given y=x²+4x+3 should be re-written in "vertex form," which is

y = a(x - h) + k, where (h, k) is the vertex.

Here y=x²+4x+3 = y=x²+4x + 4 - 4 +3 (completing the square), or

y = x^2 + 4x + 4 - 1. which condenses to   y = (x + 2)^2 - 1

Thus, h = -2 and k = 1, and so the vertex is at (h, k), or (-2, 1).  This parabola opens up.  The axis of symmetry is the vertical line  x = -2.

An alternative equation for a vertical parabola that opens up is:

y - k = 4p(x - h)^2.  Rewriting y = (x + 2)^2 - 1 to fit this form leads to:

y + 1 = 4p(x + 2)^2.  We must find the value of p that makes this equation true at any (x, y) on the graph.  Suppose we arbitrarily choose x = 1.  Then, according to y=x²+4x+3, y = 1^2 + 4(1) + 3, or y = 8 when x = 1.

Then y - k = 4p(x - h)^2 becomes 8 - 1 = 4p(1 + 2)^2, or

7 = 4p(9), or p = 7/36

The focus is thus 7/36 units above the vertex:  (-2 + 7/36), and the directrix is the horizontal line which is 7/36 units below the vertex:  y = -2 - 7/36.

Vertex:  (-2, 1)

Focus:  (-2, 2 7/36)

Directrix:  y = -2 7/36

Write a recursive and explicit rule for each geometric sequence, and then find the next 3 terms.1.) 2, 8, 32


2.) 1004, 512, 256

Answers

Hello,

1)
a_(0)=2
a_(1)=a_(0)*4=8
a_(2)=a_(1)*4=a_(0)*4^2=32
a_(3)=a_(2)*4=a_(0)*4^3=128
a_(4)=a_(3)*4=a_(0)*4^4=512
a_(5)=a_(4)*4=a_(0)*4^5=2048
...
a_(n+1)=a_(n)*4=a_(0)*4^(n+1)


2)
a_(0)=1024
a_(1)=a_(0)*0.5=512
a_(2)=a_(1)*0.5=a_(0)*0.5^(2)=256
a_(3)=a_(2)*0.5=a_(0)*0.5^(3)=128
a_(4)=a_(3)*0.5=a_(0)*0.5^(4)=64
a_(5)=a_(4)*0.5=a_(0)*0.5^(5)=32
....
a_(n+1)=a_(n)*0.5=a_(0)*0.5^(n+1)