A coach wants to know if soccer players who warm up before a game will score more points than those who don't warm up. He will break the team up into two groups and make sure each player gets equal time on the field. He will then count how many points each player makes during the game. What statistic should he study?The standard deviation of the number of points earned by each player
The standard deviation of the number of points earned by each group
The mean number of points earned by each player
The mean number of points earned by each group

Answers

Answer 1
Answer: The correct answer is the last option.

Since the coach is studying the two different groups, the results will be more meaningful if the groups are compared to one another as opposed to the players. It would also make more sense to study the mean (or average) of the points scored, rather than the standard deviation (which is essentially a measure of how spread out a set of numbers are).
Answer 2
Answer:

Answer:

The answer is The mean number of points earned by each group

Step-by-step explanation:


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To find the midpoint of a segment using the coordinates of its endpoints: Answers: A- Calculate the average of the x-coordinates and the average of the y-coordinates of the endpoints. B- Calculate the differences of the x-coordinates and the differences of the y-coordinates of the endpoints. C-Calculate the differences of the x-coordinates and the differences of the y-coordinates of the endpoints and divide each by 2. D-Calculate the average of the x-coordinates and the average of the y-coordinates of the endpoints and divide each by 2.

How many points are needed to name a specific line?

Answers

Two.

Example: a•------------------•b

You can't just call the line Line A because A is not a line, it's a point. But if you add another point, it makes a line, which would be called Line AB.

2 points to name a line .

A Geometry textbook has a mass of 48 grams.The textbook is in the shape of a rectangular prism with dimensions show below.

To find density use: density

mass

volume

5 cm

16 cm

10 cm

Determine the density of the Geometry textbook in g/cm3.

Round your answer to the nearest hundredths place.

Answers

The density of the Geometry textbook is 0.06 g/cm^3.

To find the density of the Geometry textbook in g/cm^3, we need to find its volume first. The volume of a rectangular prism is given by the formula V = l x w x h, where l is the length, w is the width, and h is the height.

In this case, the length is 16 cm, the width is 10 cm, and the height is 5 cm. Therefore, the volume of the Geometry textbook is:

V = l x w x h = 16 cm x 10 cm x 5 cm = 800 cm^3

Now, we can find the density of the textbook using the formula:

density = mass / volume

Plugging in the given mass of 48 grams and the calculated volume of 800 cm^3, we get:

density = 48 g / 800 cm^3 = 0.06 g/cm^3

Therefore, the density of the Geometry textbook is 0.06 g/cm^3. We rounded our answer to two decimal places as the original mass was given in grams to two decimal places.

Learn more about Geometry here:

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If T(n) = 6n + 2 what is the 3rd term

Answers

To find the 3rd term, just replace the 'n' with 3.

Therefore:

t(3) = 6(3) + 2
t(3) = 18 + 2
t(3) = 20.

The 3rd term is 20. 
T(n)=6n+2 T3=6(3)+2 T3=20

Ali and Kiana buried a treasure together on their school's field. The actual field is 400 feet wide. Ali made an 8-inch-wide map to record its location. Kiana made her map using a scale of 1 in. To 20 ft. On Kiana's map, the treasure is 2 inches from the south edge of the field. How far is the treasure from the south edge on Ali's map?

Answers

Answer:

The treasure is 0.8 inches from the south edge on Ali's map.

Step-by-step explanation:

Scaling factor, f = (Original length)/(Scalet length)...(i)

Let f_1 and f_2 be the scaling factors used by Ali and Kiana respectively.

Given that the field is 400 feet= 400x12 inches wide and Ali made an 8-inch-wide map to record its location.

So, f_1 = (400*12)/8=600...(ii)

Kiana made her map using a scale of 1-inch to 20 feet=20x12 inches.

So, f_2=(20*12)/1=240...(iii)

As on Kiana's map, the treasure is 2 inches from the south edge of the field,

so, from equations (i), and (ii), the original length of the treasure for the south edge of the field

=2* f_2

=2x240

=480 inches

Now, again from the equation (i) and (ii), the scaled length of the treasure on Ali's map

= 480/f_1

=480/600

=0.8 inches

Hence, the treasure is 0.8 inches from the south edge on Ali's map.

Which equation shows the distributive property? A. -5+(7+3) = (-5+7)+3


B. -3+(7+3) = (-3*2)*7


C. -3+(7+3)=-3+(3+7)



D. -5(2+9)=-5*2+(-5*9)

Answers

B is the answer to your problem

Help. Will give most Brainly.

Answers

x is 64 because the 32 is half of x. So, when it is half of x, you multiply it by 2. 32 x 2 =64 = x.

Answer:

x is 64

Step-by-step explanation:

give the award to the guy with a becaus3