1. Which of the following relations is a function?O {(1,2)(2,3)(3,5)(2,6)}
O {(4,5)(5,1)(9,5)(2,6)}
O {(4,6)(5,1)(5,9)(7,5)}
O {(4,6)(5,1)(4,3)(7,5)}

Answers

Answer 1
Answer:

Answer:

Step-by-step explanation:

first one


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I REALLY NEED HELP !!!The number of hours, t, that bacteria spread 10-fold can be modeled by the equation B(t) = B0(10)^3t. There are five bacteria present initially and a biologist wishes to find out how many hours will elapse until there are 2,000 bacteria present. What is the exact value for the number of hours elapsed, t, in the equation 2,000 = 5(10)^3t? t equals start fraction log of forty over three end fraction t equals start fraction log of two thousand over three times log of fifty end fraction t equals start fraction log of four hundred over log of three end fraction t equals start fraction log of four hundred over three end fraction
Can you please help me with this
5x+2y=7 7x+2y=5 i need it right

What is a soliloquy in a drama?

Answers

this is not mathematics but ok......
soliloquy is when someone on stage speaks to them self as if thinking in their mind, expressing their thoughts and emotions, conveying them to the audience.

Answer:


Step-by-step explanation:

soliloquy is when someone on stage speaks to them self as if thinking in their mind, expressing their thoughts and emotions, conveying them to the audience.

Which of these is the algebraic expression for the verbal expression "ten times the difference of a number and twelve?"10(x − 12)
x − 12 ⋅ 10
12(x − 10)
10 ⋅ x − 12

Answers

Hello,

Answer A

10*(x-12)
first x-12 (parenthesis) : difference of some number and 12
second 10* the result before==> the product of 10 by the diffrence of x and 12.


Answer:

Step-by-step explanation:

10(x − 12)

x − 12 ⋅ 10

12(x − 10)

10 ⋅ x − 12

mike has 350.75 while jane has 250.25 .if they spent together a total amout of 295.50 and saved remaining amount how much they put together in the saving box?

Answers

Answer:

305.5

Step-by-step explanation:

350.75 + 250.25 = 601

601 - 295.50 = 305.50

Andrew borrows $79,500 for 5 months on 6.30% interest rate in his saving account. calculate the simple interest

Answers

Equation i= p time r time T 79500 time .0630 time .42 Equal 21,035.7 simple interest Dos Doctor pepper on the interest, going back two time on the left which would become .0630 5 divide month of 12 which is .41666 Round to the nearest tenth which is .42

Final answer:

The simple interest on a $79,500 loan borrowed for 5 months at a 6.30% interest rate is $25,087.50.

Explanation:

To calculate the simple interest, we can use the formula: Simple Interest = Principal Amount * Rate * Time. In this case, the principal amount is $79,500, the rate is 6.30%, and the time is 5 months. First, convert the rate to a decimal by dividing it by 100: 6.30/100 = 0.063. Then, substitute the values into the formula: Simple Interest = $79,500 * 0.063 * 5 = $25,087.50.

Learn more about Simple Interest here:

brainly.com/question/22621039

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Olivia runs 15 miles in 3 hours how many miles will she run in 8 hours if she stays the same rate

Answers

Answer:

Olivia will run 40 miles in 8 hours if she maintains the same rate.

Step-by-step explanation:

If Olivia runs 15 miles in 3 hours at a constant rate, we can find her rate of running:

Rate = Distance / Time

Rate = 15 miles / 3 hours

Rate = 5 miles per hour

Now, we can use this rate to calculate how many miles Olivia will run in 8 hours:

Distance = Rate × Time

Distance = 5 miles/hour × 8 hours

Distance = 40 miles

Olivia will run 40 miles in 8 hours if she maintains the same rate.

Answer:

If Olivia stays running at the same rate, She will run 40 miles in 8 hours.

If this helped you let me know. If not, I will improve and make sure my work is correct. Have a nice day!

PLEASE HELP WITH ALGEBRA

Answers

   y - y₁ = m(x - x₁)
y - (-7) = -1¹/₅(x - (-3))
   y + 7 = -1¹/₅(x + 3)
   y + 7 = -1¹/₅(x) - 1¹/₅(3)
   y + 7 = -1¹/₅x - 3³/₅

m = (y_(2) - y_(1))/(x_(2) - x_(1)) = (-17 - (-2))/(3 - (-9)) = (-17 + 2)/(3 + 9)} = (-15)/(12) = (-5)/(4) = -1(1)/(4)

   y - y₁ = m(x - x₁)
y - (-2) = -1¹/₄(x - (-9))
   y + 2 = -1¹/₄(x + 9)
   y + 2 = -1¹/₄(x) - 1¹/₄(9)
   y + 2 = -1¹/₄x - 11¹/₄
       - 2               - 2
         y = -1¹/₄x - 13¹/₄

   y - y₁ = m(x - x₁)
y - (-3) = ⁻¹/₄(x - 8)
   y + 3 = ⁻¹/₄(x) + ¹/₄(8)
   y + 3 = ⁻¹/₄x + 2
       - 3           - 3
         y = ⁻¹/₄x - 1

     y - y₁ = m(x - x₁)
y - (-17) = ¹/₂(x - (-6))
   y + 17 = ¹/₂(x + 6)
   y + 17 = ¹/₂(x) + ¹/₂(6)
   y + 17 = ¹/₂x + 3
       - 17          - 17
          y = ¹/₂x - 14

m = (y_(2) - y_(1))/(x_(2) - x_(1)) = (-4 - 8)/(-4 - 6) = (-12)/(-10) = (12)/(10) = (6)/(5) = 1(1)/(5)

y - y₁ = m(x - x₁)
 y - 8 = 1¹/₅(x - 6)
 y - 8 = 1¹/₅(x) - 1¹/₅(6)
 y - 8 = 1¹/₅x - 7¹/₅
   + 8            + 8
      y = 1¹/₅x + ⁴/₅