Answer:
a) Critical value = -1.285
b) We should reject null hypothesis that the mean equals 0.32
Step-by-step explanation:
Given that the statistic of z equals negative 2.40 is obtained when testing the claim that less than 0.32
i.e. for hypotheses
(one tailed test at 10% significance level)
Z critical value for 90% one tailed = -1.285
Since our test statistic is less than -1.285 we reject null hypothesis
a) Critical value = -1.285
b) We should reject null hypothesis that the mean equals 0.32
Solution:
Since 5 pounds of meat will feed about 26 people.
Thus;
If she is expecting 156 people, she should prepare;
ANSWER: 30lb
3 2/3 ÷ 1 1/4
Make the two mixed fractions into an improper fraction
Denominator times whole number. 3*3=9. Add 9 with the numerator. 9+2=11
1*4=4 . 4+1=5
11/3 ÷ 5/4
Flip over the second fraction only when dividing
11/3 *4/5
Multiply the numerator together. Multiply the denominator together.
11*4=44
3*5=15
44/15 or 2 14/15
Answer: 44/15 or 2 14/15
Step-by-step explanation:
Change into improper fractions:
Change to a multiplication problem:
Simplify:
or
or 2.93333333333
Depends on how the question wants you to put it. You can put it as an improper fraction, a proper fraction, or as a decimal.
Hope this helped ; )
Answer: 0.0080
Step-by-step explanation:
Given : The manufacturer's website states that the average weight of each stick is oz with a standard deviation of oz.
We assume the weight of the drumsticks is normally distributed.
Using formula , the z-value corresponds x=2.66 will be :-
By using the standard normal distribution table for z, we get
P-value =
Hence, the probability of the stick's weight being 2.66 oz or greater=0.0080