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(e) Which sample contains more atoms: 2.0 g of Fe2O3 or 2.0 g of CaSO4? Support your answer with calculations.

Answers

Answer 1

Answer:

CaSO4. It has 6 atoms while Fe2O3 has 5 atoms

Explanation:

Fe2O3 contains 2 atoms of Iron(Fe) and 3 atoms of Oxygen(O) = 2 + 3 = 5 atoms

CaSO4 contains 1 atom of Calcium(Ca), 1 atom of Sulphur(S) and 4 atoms of Oxygen(O) = 1 + 1 + 4 = 6 atoms

Further Explanation

The ideal gas equation is an equation that presents the relationship between the pressure and volume of a gas with the temperature and the number of moles of the gas itself. This ideal gas equation is based on the laws of Boyle, Charles, and Avogadro.

This equation is generally written as

-PV = nRT

Boyle's Law (T = C)

Boyle's Law about the nature of gas was first created by Robert Boyle (1627¡1691). Boyle found experimentally that at a constant temperature, the pressure in a closed container would be inversely proportional to the volume of the gas. This means that if we press the gas and large volumes to small volumes, the gas pressure will rise, conversely if we expand the gas from small volumes to large volumes, the gas pressure will decrease. The process of pressing gas from large volumes to small volumes is called the compression process. While the process of changing the volume of gas from a small volume into a large volume is called the expansion process.

Gay Lussac Law (V = C)

The Gay Lussac Law was first coined by Joseph Louis Gay-Lussac (1778 - 1850) a chemist from France. Lussac's Gay Law states that under constant volume conditions, an increase in gas pressure will be directly proportional to an increase in gas temperature. This means that the gas in a closed container with a volume does not change (V0 = V1), so if the gas is heated from the initial temperature T0 to the final temperature T1 will cause the gas pressure also rises from the initial pressure (p0) to the final pressure (p1).

Charles Law (P = C)

Charles' ideal gas law is also called the law of constant pressure, first created by Jacques Alexandre Cesar Charles (1746 - 1823) a chemist from France. Charles's Law says "Under conditions of constant gas pressure, the volume of a gas will increase in proportion to the increase in temperature of the gas". This means that if we have a cylinder-piston system that can move up and down freely, then when the gas in the system is heated so that the temperature rises from T0 to T1, then to keep the gas pressure in the cylinder constant, the volume of gas will expand from the condition V0 to V1.

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The ideal gas equation brainly.com/question/10599201

Details

Grade: College

Subject: Chemistry

keywords: Gas, the ideal gas.

What type of hybridization is needed to explain why ethyne, C2H2, is linear?

Answers

When C-C is having a triple bond the hybridization is sp. But I am not sure how to relate that to the linear shape.

Balance the chemical equation given below, and determine the number of moles of iodine that reacts with 10.0 g of aluminum._____ Al(s) + _____ I2(s) → _____ Al2I6(s)

Answers

Answer:

1. 2Al + 3I2 —> Al2I6

2. 0.555mol of I2

Explanation:

1. Al + I2 —> Al2I6

Observing the above equation, there are 2 atoms of Al on the right side and 1 on the left side. To balance it, put 2 in front of Al as shown below:

2Al + I2 —>Al2I6

Also, there are 6 atoms of I on the right side and 2 on the left side. To balance it, put 3 in front I2 as shown below:

2Al + 3I2 —>Al2I6

2. Molar Mass of Al = 27g/mol

Mass of Al = 10g

n = Mass /Molar Mass

n = 10/27 = 0.37mol

From the equation,

2moles of Al reacted with 3 moles of I2.

Therefore, 0.37mol of Al will react with = (0.37 x 3)/2 = 0.555mol of I2

The balanced chemical equation is:

2 Al(s) + 3 I₂(s) → Al₂I₆(s)

0.557 moles of iodine react with 10.0 g of aluminum.

Let's consider the following unbalanced equation.

Al(s) + I₂(s) → Al₂I₆(s)

We will balance it using the trial and error method. We can get the balanced equation by multiplying Al by 2 (balance Al atoms) and I₂ by 3 (balance I atoms).

2 Al(s) + 3 I₂(s) → Al₂I₆(s)

The molar mass of Al is 26.98 g/mol. The moles corresponding to 10.0 g of Al are:

$10.0 g * (1mol)/(26.98g) = 0.371 mol$