MATHEMATICS HIGH SCHOOL

What are the coordinates of the y-intercept of the line whose equation is LaTeX: 12x+13y=812 x + 13 y = 8? ( , )

Answers

Answer 1

Answer:

The coordinates of the y-intercept of the line whose equation is

12 x + 13 y = 8 is 8/13.

As given in the question,

Given equation: 12x + 13 y=8

Convert the equation into y-intercept form

General form of y-intercept form is

y=mx + b

Subtract from the equation 12x from both the side of equation,

12x+13y-12x=-12x+8

⇒ 13y=-12x +8

Divide both the side by 13

13y/13= (-12/13)x +8/13

⇒y=(-12/13)x +8/13

To get y-intercept put x=0

y =8/13

Therefore, thecoordinates of the y-intercept of the line whose equation is 12 x + 13 y = 8 is 8/13.

The complete question is :

What are the coordinates of the y-intercept of the line whose equation is

12 x + 13 y = 8 ?

Learn more about y- intercept here

brainly.com/question/14180189

#SPJ1

Related Questions

A soup can has a height of 4 inches and a diameter of 3 inches. Which of the following is the closest to the volume of the soup can?
Somebody help please ASAP!
What is the solution of this linear system?3x + 5y = -1 2x − 5y = 16 (-3, 2) (-3, -2) (3, -2) (2, -3)
Which of the following equations is of a parabola with a vertex at (0, 3)?
What is the slope of the line represented by the equation y + 3 = -4(x - 5)?

HELP!!! Using a directrix of y = 2 and a focus of (3, −4), what quadratic function is created?

Answers

Answer:

The required quadratic function is $y=-(1)/(12)(x-3)^2-1$ .

Step-by-step explanation:

The standard form of the parabola is

$(x-h)^2=4p(y-k)$

Where the focus is (h, k + p) and the directrix is y = k - p.

The directrix of y = 2 and a focus of (3, −4).

$(h,k+p)=(3,-4)$

On comparing both sides we get

$h=3$

$k+p=-4$ ...... (1)

$y=k-p$

$k-p=2$ ...... (2)

Add equation (1) and (2).

$2k=-2$

$k=-1$

Substitute k=-1 in equation (1).

$(-1)+p=-4$

$p=-3$

Therefore the equation of parabola is

$(x-3)^2=4(-3)(y-(-1))$

$(x-3)^2=-12(y+1)$

It can be rewritten as

$y=-(1)/(12)(x-3)^2-1$

Therefore the required quadratic function is $y=-(1)/(12)(x-3)^2-1$ .

parabola with vertx (3,-1) that opens down

4(-3)(y+1)=(x-3)^2
y+1=(-1/12)(x-3)^2
y=(-1/12)(x-3)^2-1

Slope intercept form

Answers

Given:

The equation of the parallel line is

$y=-(5)/(2)x+7$

The required line passes through the point (-4,1).

To find:

The equation of line in slope slope intercept form.

Solution:

The slope intercept form of a linear function is

$y=mx+b$

Where m is slope and b is y-intercept.

On comparing the equation $y=-(5)/(2)x+7$ with slope intercept form, we get

$m=-(5)/(2)$

We know that the slopes of parallel lines are always same. So, the slope of the required line is $m=-(5)/(2)$ .

The line passes through the point (-4,1) with slope $m=-(5)/(2)$ . So, the equation of line is

$y-y_1=m(x-x_1)$

$y-(1)=-(5)/(2)(x-(-4))$

$y-1=-(5)/(2)(x+4)$

$y-1=-(5)/(2)x-10$

Adding 1 on both sides, we get

$y=-(5)/(2)x-10+1$

$y=-(5)/(2)x-9$

Therefore, the correct option is C.

The hands of a clock form the same angle at various times of the day. For example, the angle formed at 2:00 is congruent to the angle formed at 10:00. If a clock has a diameter of 1 ft, what is the distance along the edge of the clock from the minute hand to the hour hand at 2:00? Give your answer in exacts.

Answers

it is 2 inches long this is because of the length of the hands .

The length of line segment AK is 640 meters. ∆ABC, ∆CDF, and ∆FJK are similar, and 2AC = CF = 2FK. The first pillar is 20 meters tall. What is the area of ∆CDF

Answers

A to K = 640 meters

2AC = CF = 2FK

2AC = 2(160) = 320
CF = 320
2FK = 2(160) = 320

AC = 160
CF = 320
FK = 160
AK 640

BG = 20 m ; Area = (160m*20m) / 2 = 3,200/2 = 1,600 m²

20:160 = x : 320
20*320 = 160x
6,400 = 160x
6,400/160 = x
40 = x

Area of CDF = (320m*40m) / 2 = 12,800 / 2 = 6,400 m²

Answer:

what that other guy said

sorry just here for the points

Rotating a triangle by 50 degrees will change the measures of the exterior angles by _________.A. -50 degrees
B. 50 degrees
C. 0 degrees

Answers

c it will not change its still a triangle

Set up a proportion to solve for x in the following similar triangles.

Answers

Final answer:

The correct option is d.

To solve for x in similar triangles ABC and PQR, set up the proportion AB/PQ = DC/QR and solve for x.

Explanation:

To set up the proportion to solve for x in similar triangles ABC and PQR, we need to compare the corresponding sides. AB corresponds to PQ, so we can set up the proportion as follows:

AB/PQ = DC/QR

Substituting the given values, the proportion becomes:

18/12 = 24/(x-2)

Simplifying further, we can solve for x by cross multiplying and solving the resulting equation.

Learn more about Similar Triangles here:

brainly.com/question/14926756

#SPJ2

The complete question is given below:

It is given that two triangles are similar, ABC and PQR. AB= 18 units and DC= 24 units. PQ= 12 units and QR= x-2 units. Set up a proportion to solve for x in the following similar triangles.

a. 18/24 = (x-2)/12

b. 18/12 = (x-2)/24

c. 18/12 = 24/(x-2)

d. 18/12 = 24/x - 2

Answer:

Step-by-step explanation:

I took the quiz and it was C! Hope this helps :)

Other Questions

What is the sum of a number and 37?

What is the ratio of 5 hours to 100 minutes

The cost to mail a one ounce letter was 39 cents and the cost to mail a two once letter was 63 cents. What is the ratio of the cost to mail a one ounce letter to the cost to mail a two ounce letter

Can someone explain lesson 6.3 math boxes in everyday math regarding the missing numbers on the number lines